The Equation is
Q x + P= 33 x+25
As both sides are equations in one variable , Comparing like terms of both sides gives,
→ Q x = 33 x
→ Q =33
And , P=25
But for this Equation to have no solution , Q must be equal to 33 and P should not be equal to 25.
Q=33,∧ P≠25 i.e any real number not equal to 25.P∈(-∞,∞)but P≠25
Answer:
47.746, answer choice C
Step-by-step explanation:
47.746
Should be A if I’m not mistaken
<span>A. 1040
1040 is the form that you can itemized deductions which is where you deduct charitable contributions.
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Answer:
and 
Step-by-step explanation:
The given complex number equation is:
We simplify the LHS and compare with the RHS
We collect LCD on the left to get:
Simplify to get:
Rationalize the LHS:
Expand the numerator using the distributive property and the denominator using difference of two squares.
Simplify to get:
By comparing real parts and imaginary parts; we have;
and
