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leonid [27]
3 years ago
6

What is the sum?

Mathematics
1 answer:
gavmur [86]3 years ago
5 0

Answer:

The answer is option D.

Step-by-step explanation:

First we must first find the LCM

the LCM of x² - 9 and x + 3 is x² - 9

So we have

\frac{3}{ {x}^{2} - 9 }  +  \frac{5}{x + 3}  =   \frac{3 + 5(x - 3)}{ {x}^{2}  - 9}  \\  \\  =  \frac{3 + 5x - 15}{(x + 3)(x - 3)}    \\  \\  = \frac{5x - 12}{(x +  3)(x - 3)}

Hope this helps you

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Write an expression to show 9 less than the sum of t and h.​
Dafna11 [192]

Answer:

(t + h) - 9

Step-by-step explanation:

I am pretty sure that the answer is

(t + h) - 9

Tell me if I am wrong

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Because the two distributions displayed below have different ranges, they have the different standard deviations.
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False, the range is just determined by minising the lowest from the highest, but the variables can still get you the same mean, which can lead to the same standard deviation
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jarptica [38.1K]
<h3>1.Area of the parallelogram= 288 square units</h3><h3>2.Area of the parallelogram=45 m^2</h3><h3>3.Area of the trapezoid   = 34 square in.</h3><h3>4.Area of the trapezoid = 8 square ft</h3><h3>5.Area of the rhombus= 27 square cm</h3><h3>6.Area of the rhombus= 108 square in</h3><h3>7.The area of the desktop is  = 1200 square in</h3><h3>8.The area of the rhombus is =84 cm^2</h3><h3>9.Area of the trapezoid  = 240 square ft</h3>

Step-by-step explanation:

1.

Base =16 ft and Height = 18 ft

Area of the parallelogram = base × height

                                       =16× 18 square units

                                       = 288 square units

2.

Base = 9 m and height = 5 m

Area of the parallelogram = base × height

                                        =(9×5) m^2

                                         =45 m^2

3 .

Height = 4 in and parallel sides are 12 in and 5 in

Area of the  trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                            =\frac{1}{2} \times (12+5) \times 4 square in.

                             = 34 square in.

4.

Height = 2 ft  and parallel sides are 2 ft and 6 ft

Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                              =\frac{1}{2} \times (2+6) \times 2 square ft

                              = 8 square ft

5.

Diagonals are 6 cm and 9 cm.

Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 6\times 9 square cm

                               = 27 square cm

6. Diagonals are 12 in and 18 in

Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 12\times 18 square in

                               = 108 square in

7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in

The area of the desktop is = (30 × 40 ) square in

                                            = 1200 square in

8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.

The area of the rhombus = \frac {1}{2} \times 14 \times 12 cm^2

                                         =84 cm^2

9.Given , the base of trapezoid are 24 ft  and 16 ft and height is 12 ft

Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                                    = \frac{1}{2} \times (24+16) \times 12 square ft

                                     = 240 square ft

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Answer:

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Step-by-step explanation:

20% is equal to 0.2. You multiply 64 by 0.2. I hope this helps.

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