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n200080 [17]
3 years ago
15

K=100N/m, alungirea delta l=10cm, calculati forta elastica

Physics
1 answer:
Doss [256]3 years ago
4 0

Explanation:

this is the answer for question .

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A uniform disk is constrained to rotate about an axis passing through its center and perpendicular to the plane of the disk. If
katrin2010 [14]

A uniform disk is constrained to rotate about an axis passing through its center and perpendicular to the plane of the disk. If the disk starts from rest and is then brought in contact with a spinning rubber wheel, we observe that the disk gradually begins to rotate too. If after 35 s of contact with this spinning rubber wheel, the disk has an angular velocity of 4.0 rad/s, find the average angular acceleration that the disk experiences. (Assume the positive direction is in the initial direction of rotation of the disk. Indicate the direction with the sign of your answer.)

Assume after 35 s of contact with this spinning rubber wheel, the disk has an angular velocity of 11.0 rad/s.

Answer:

385 rad

Explanation:

The expression for the angular acceleration of a disk that is in contact with a spinning wheel can be given as:

\alpha = \frac{\delta \omega}{\delta t}

where \delta\omega = \omega_f - \omega_i

\alpha = \frac{ \omega_f-\omega_i}{\delta t}

\alpha = \frac{ 4.0 rad/s-0 rad/s}{35}

\alpha =0.14 rad/s^2

Angular displacement of a disk can be calculated by using the formula:

\theta = \omega t

substituting 11.0 rad/s for \omega and t = 35 s ; we have:

\theta = 11.0 rad/s * 35 s

\theta = 385 rad

4 0
3 years ago
Read 2 more answers
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