The motion of an apple when it falls from a tree is
b) Accelerating
The motion of apple is when it falls from a tree is the case of free fall.
During free fall , the initial velocity of the apple or any object is zero but it gains some velocity due to gravitatonal acceleration .
Complete question:
Consider the hypothetical reaction 4A + 2B → C + 3D
Over an interval of 4.0 s the average rate of change of the concentration of B was measured to be -0.0760 M/s. What is the final concentration of A at the end of this same interval if its concentration was initially 1.600 M?
Answer:
the final concentration of A is 0.992 M.
Explanation:
Given;
time of reaction, t = 4.0 s
rate of change of the concentration of B = -0.0760 M/s
initial concentration of A = 1.600 M
⇒Determine the rate of change of the concentration of A.
From the given reaction: 4A + 2B → C + 3D
2 moles of B ---------------> 4 moles of A
-0.0760 M/s of B -----------> x
⇒Determine the change in concentration of A after 4s;
ΔA = -0.152 M/s x 4s
ΔA = -0.608 M
⇒ Determine the final concentration of A after 4s
A = A₀ + ΔA
A = 1.6 M + (-0.608 M)
A = 1.6 M - 0.608 M
A = 0.992 M
Therefore, the final concentration of A is 0.992 M.
As the wave travels through different media, its speed and wavelength change, and its frequency remains constant.
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Answer:
The kite string is feet long.
Explanation:
Use the Pythagorean Theorem, which is .
Here the question is asking for , which would be the hypotenuse, or the longest side of the triangle.
So the would be , and the would be .
Plug those values into the formula, and that would get .
Now, solve for , which would equal .
That means we would have to solve for .
Square root both sides of the equation, getting .
Solve for , which would get us .
Hence, the answer to this would question would be .
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Given
Car 1
m1 = 1300 kg
v1 = 20 m/s
m2 = 900 kg
v2 = -15 m/s
(Negative sign shows that direction of car 2 is opposite to car 1)
Procedure
As per the conservation of linear momentum, "The total momentum of the system before the collision must be equal to the total momentum after the collision". And this applies to the perfectly inelastic collision as well. Then the expression is,
Thus, we can conclude that the speed and direction of the cars after the impact is 5.68 m/s towards the first car.