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adelina 88 [10]
2 years ago
5

I need help with my math problems

Mathematics
1 answer:
nekit [7.7K]2 years ago
3 0

Answer:

Step-by-step explanation:

X       Y                    X           Y    

0       3                     0           5

1        7                     1              8

2        11                    2           11

3        15                   3          14

4         19                   4            17  

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Find the area of this parallelogram, top= 14 left= 11 right = 10
Kamila [148]

Answer:

140 cm^2

Step-by-step explanation:

Formula for area of a Parallelogram: base*height

14 cm * 10cm = 140 cm^{2}

4 0
2 years ago
3 2<br> - x. - =<br> 10 3<br> Solve and simplify
Grace [21]

6......................................... i mean this is probably wrong but yeah

8 0
2 years ago
Line FG contains points F (3,7) and G (-4,-5) line HI contains points (-1,0) and I (4,6) lines FG and HI are. ?
ludmilkaskok [199]
FG : (3,7)(-4,-5)
slope = (-5 - 7) / (-4-3) = -12/-7 = 12/7

y = mx + b
slope(m) = 12/7
(3,7)...x = 3 and y = 7
now we sub, we r looking for b, the y int
7 = 12/7(3) + b
7 = 36/7 + b
7- 36/7 = b
49/7 - 36/7 = b
13/7 = b
so ur equation is : y = 12/7 + 13/7.....slope = 12/7, y int = 13/7

HI : (-1,0)(4,6)
slope = (6 - 0) / (4 - (-1) = 6/5

no need to go any farther.....these lines have different slopes...and their not negative reciprocals....so there will be one solution. Answer is : neither.
7 0
2 years ago
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Two identical masses are moving down a slope one masses traveling twice as fast as the other mass how does the kinetic energy of
GaryK [48]

Answer:

One mass's kinetic energy is 4 times the other.

Step-by-step explanation:

The formula for kinetic energy is KE=\frac{1}{2}mv^2

Where

KE is the kinetic energy

m is the mass

v is the velocity

  • Now, let mass of the first be m (second is identical so mass of 2nd is m as well)
  • Let velocity of the first one be v. Since 2nd one is travelling twice as fast, its velocity will be 2v

<u>KE of 1st mass is:</u>

\frac{1}{2}mv^2

<u />

<u>KE of 2nd mass is:</u>

\frac{1}{2}m(2v)^2\\=\frac{1}{2}m(4v^2)\\=\frac{1}{2}mv^2 * 4

Hence, the kinetic energy of the 2nd mass is 4 times the first.

6 0
3 years ago
What is 7.39 rounded to the nearest whole number?
lutik1710 [3]
7 is the answer 4 and lower you round down 5 and up is up
5 0
3 years ago
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