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Romashka [77]
3 years ago
13

Fractions and mixed numbers I need help!!!

Mathematics
1 answer:
zimovet [89]3 years ago
7 0

Answer:

The answer would be D, or 3^{3} *3^{2}* 5

Step-by-step explanation:

A is 540

B is 30

C is 720

D is 360

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Here is the work to solve

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Brent went for a bicycle ride. The clocks show his start time and his
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He rode his bicycle for <u>4</u><u>0</u><u>m</u><u>i</u><u>n</u><u>u</u><u>t</u><u>e</u><u>s</u>

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What's the answer for 3/4 (x+3)=9
Vitek1552 [10]
We want to solve the equation :

\displaystyle{  \frac{3}{4}(x+3)=9


first, multiply both sides by 4:

\displaystyle{ \cancel{4} \cdot \frac{3}{ \cancel 4 }(x+3)=4\cdot 9

\displaystyle{ 3(x+3)=36


divide both sides by 3:

x+3=12


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3 0
3 years ago
Please answer fast, I need great answers!!!!! This is mathematics.
Fantom [35]
20, 25, 30, 30, 31, 40, 41, 49
median = 30.5

lower IQR = 27.5
upper IQR = 40.5

Range IQR = 40.5 - 27.5 = 13

answer is 13
7 0
2 years ago
Simplify:<br> (4p3 + 6p2 – 7) – (8p? – 7 – 3p)
Kipish [7]

Answer:

4p3 + 6p2 - 8p - 7

Step-by-step explanation:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "p2"   was replaced by   "p^2".  1 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

 (((4 • (p3)) +  (2•3p2)) -  7) -  8p

STEP

2

:

Equation at the end of step

2

:

 ((22p3 +  (2•3p2)) -  7) -  8p

STEP

3

:

Checking for a perfect cube

3.1    4p3+6p2-8p-7  is not a perfect cube

Trying to factor by pulling out :

3.2      Factoring:  4p3+6p2-8p-7

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -8p-7

Group 2:  4p3+6p2

Pull out from each group separately :

Group 1:   (8p+7) • (-1)

Group 2:   (2p+3) • (2p2)

3.3    Find roots (zeroes) of :       F(p) = 4p3+6p2-8p-7

Polynomial Roots Calculator is a set of methods aimed at finding values of  p  for which   F(p)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  p  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  4  and the Trailing Constant is  -7.

The factor(s) are:

of the Leading Coefficient :  1,2 ,4

of the Trailing Constant :  1 ,7

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        3.00    

     -1       2        -0.50        -2.00    

     -1       4        -0.25        -4.69    

     -7       1        -7.00       -1029.00    

     -7       2        -3.50        -77.00    

     -7       4        -1.75        3.94    

     1       1        1.00        -5.00    

     1       2        0.50        -9.00    

     1       4        0.25        -8.56    

     7       1        7.00        1603.00    

     7       2        3.50        210.00    

     7       4        1.75        18.81    

Final result :

 4p3 + 6p2 - 8p - 7

5 0
2 years ago
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