Question

6. A super-bouncy-ball is thrown 25m into the air. The ball falls, rebounds to 70% of the height of the previous bounce and falls again. If the ball continues to rebound and fall in this manner, find the total distance the ball has travelled after it hits the ground the 5th time. This may be answered in decimal form. Round your answer to 2 decimal places.

Answer 1

Answer:

The total distance the ball has travelled after it hits the ground the 5th time is of 48.53m.

Step-by-step explanation:

Geometric sequence:

In a geometric sequence, the quotient of consecutive terms is the same. The nth term of a geometric sequence is given by:

$a_n = a_1q^{n-1}$

In which $a_1$ is the first term and $q$ is the common ratio.

A super-bouncy-ball is thrown 25m into the air. The ball falls, rebounds to 70% of the height of the previous bounce and falls again.

This means that:

$q = 0.7, a_1 = 25*0.7 = 17.5$

Then

$a_n = a_1q^{n-1}$

$a_n = 17.5(0.7)^{n-1}$

First 5 terms:

$a_1 = 17.5$

$a_2 = 17.5(0.7)^{2-1} = 12.25$

$a_3 = 17.5(0.7)^{3-1} = 8.58$

$a_4 = 17.5(0.7)^{4-1} = 6$

$a_5 = 17.5(0.7)^{5-1} = 4.2$

Find the total distance the ball has travelled after it hits the ground the 5th time.

$T = 17.5 + 12.25 + 8.58 + 6 + 4.2 = 48.53$

The total distance the ball has travelled after it hits the ground the 5th time is of 48.53m.