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Aleksandr-060686 [28]
3 years ago
9

Is it true 4 and -4 have a sum of 0

Mathematics
1 answer:
mafiozo [28]3 years ago
3 0

Answer:

Yes, 4 + -4 = 0.

Think of it like a number line: The number four is 4 units to the right of the center which is 0, and the number negative four is 4 units to the left of the center. When you add them together, those distances cancel out, and you just get 0.

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If 3(n+8)=36 what is the value of n
Ronch [10]

Answer:

Thus, n = 4 is the solution.

Step-by-step explanation:

1.  perform the indicated multiplication, obtaining 3n + 24 = 36

2.  Subtract 24 from both sides:   3n = 12

3.  Solve this result for n:  n = 12/3.  Thus, n = 4 is the solution.

4 0
4 years ago
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What is the length of LJ?<br> the choices are <br> 23.0<br> 17.0<br> 4.7<br> 3.5
tatiyna
4.7

It just is.....
It is what it is.....
7 0
3 years ago
If events X and Y are independent, what must be true? Check all that apply. P(Y | X) = 0 P(X | Y) = 0 P(Y | X) = P(Y) P(Y | X) =
lana [24]

if events X and Y are independent, then for intersection we multiply the probability

P(Y∩X)  = P(Y) * P(X)

We know that

P(Y|X) =\frac{P(YintersectionX)}{P(X)}

Now we replace P(Y) * P(X) for  P(Y∩X)

P(Y|X) =\frac{P(Y)*P(X)}{P(X)}

Cancel out P(X)

So P(Y|X) = P(Y)

Like that

P(X|Y) =\frac{P(XintersectionY)}{P(Y)}

Now we replace P(X) * P(Y) for  P(X∩Y)

P(X|Y) =\frac{P(X)*P(Y)}{P(Y)}

Cancel out P(Y)

So P(X|Y) = P(X)

P(Y | X) = P(Y)  and P(X | Y) = P(X)  are true



3 0
3 years ago
Read 2 more answers
1. Avital counted 40 green cars and 20 silver cars in the parking lot. If the number of green cars stay the same, how many more
Luba_88 [7]
X represents the number that would be added to the silver cars.


x/40= 4
X=40x4
x=160

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8 0
3 years ago
Factorize a^2b^2-c^2
Elden [556K]
<h3>Answer:  (ab - c)(ab + c)</h3>

===================================================

Work Shown:

a^2b^2 - c^2

(ab)^2 - c^2

(ab - c)(ab + c)

In the last step, I used the difference of squares factoring rule.

4 0
3 years ago
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