(2x-8)times(3x-2) pls help
2 answers:
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y = log(3x + 4) + 2
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Y-INTERCEPT: set x = 0
y = log(3(0) + 4) + 2
y = log(0 + 4) + 2
y = log( 4) + 2
Using calculator,
y = log( 4) + 2
y ≈ 2.60 when x = 0
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X-INTERCEPT: set y = 0
y = log(3x + 4) + 2
0 = log(3x + 4) + 2
-2 = log(3x + 4)
(it's simple. Always remember that the base is 10, even though there seems to be no "smaller number" next to log)
= 3x + 4
- 4 = 3x
[ - 4 ] /3 = x
x = -1.33 when y = 0
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<h3>ANSWER: y-intercept is 2.60 and x-intercept is -1.33</h3>