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2 years ago

Christel wants to know what the most popular color at her school is. She surveys students grades 1,2,3.

Mathematics

1 answer:

shutvik [7]2 years ago

7 0

Answer:

It will be biased.

Step-by-step explanation:

By surveying only grades 1, 2, and 3, she is not taking a representation of the entire school. It is possible that the popular color or the color the students like would change over time and the opinion of the younger kids could be different from that of the older kids. Therefore, the sample is biased unless she surveys students from all grades.

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The probability of event A is 0.47. The probability of event B is 0.31. If the two events are mutually exclusive,

Advocard [28]

Answer:

Step-by-step explanation:

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2 years ago

Which one of the following is true when ds/st =3t^2/2s

Zina [86]

Middle school math! I actually know how to teach differential calculus to middle schoolers, but I wouldn't start with this example, where we're gonna have to integrate eventually.

We have

$\dfrac{ds}{dt} = \dfrac{3t^2}{2s}$

We have an odd mix of s and t on the right, which means this probably was an implicit derivative to begin with. In other words, instead of s as a function of t, we have some equation of s and t that is satisfied.

We move the variables to their respective sides

$2s \ ds = 3t^2 dt$

Integrating,

$s^2 =t^3 + C$

We only need one constant of integration.

I won't bother to write the square root. This is choice D.

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3 years ago

use digits to write a number for the following. : seven tenths . three hundreths, and eight thousandths and then (. )

kondor19780726 [428]

Answer:

0.0378

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2 years ago

Find the first four terms of the sequence given by the following. aₙ=43-3(n-1) n=1,2,3. . .

Serggg [28]

Given :-

The general term of a sequence is given by aₙ=43-3(n-1) .

To Find :-

The first four terms of the sequence.

Solution :-

The given expression is $/$

→ aₙ=43-3(n-1)

where n > 0

Finding the first term :

Substituting n = 1 , we have ,

→ T1 = 43 - 3(1-1)

→ T1 = 43 - 3*0

→ T1 = 43 - 0 = 43

Finding the second term :

Substituting n = 2 , we have,

→ T2 = 43 -3(2-1)

→ T2 = 43 -3*1

→ T2 = 43 -3 = 40

Finding the third term :

Substituting n = 3 , we have,

→ T3 = 43 -3(3-1)

→ T3 = 43 -3*2

→ T3 = 43 -6 = 37

Finding the fourth term :

→ T4 = 43 -3(4-1)

→ T4 = 43 -3*3

→ T4 = 43-9 = 34

Hence the first four terms of the sequence are 43 , 40 , 37 and 34 .

I hope this helps . Let me know if you need further clarification .

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2 years ago

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levacccp [35]

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