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77julia77 [94]
2 years ago
6

Christel wants to know what the most popular color at her school is. She surveys students grades 1,2,3.

Mathematics
1 answer:
shutvik [7]2 years ago
7 0

Answer:

It will be biased.

Step-by-step explanation:

By surveying only grades 1, 2, and 3, she is not taking a representation of the entire school. It is possible that the popular color or the color the students like would change over time and the opinion of the younger kids could be different from that of the older kids. Therefore, the sample is biased unless she surveys students from all grades.

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(5 Points)<br> all (1 – 3K)<br> -396<br> 0-374<br> 0 -198<br> 0 -187
Triss [41]

Answer:−3K−395,−374,−198,−187

Step-by-step explanation:

Remove parentheses.

1−3K−396,0−374,0−198,0−187

Simplify  1-3K-3961−3K−396  to  -3K-395−3K−395.

−3K−395,0−374,0−198,0−187

Simplify  0-3740−374  to  -374−374.

−3K−395,−374,0−198,0−187

Simplify  0-1980−198  to  -198−198.

−3K−395,−374,−198,0−187

Simplify  0-1870−187  to  -187−187.

−3K−395,−374,−198,−187

6 0
3 years ago
Which of the following are solutions to the equation below? Check all that apply. 15x2 - 44x + 32 = 0
krek1111 [17]
If you want to find the solutions for this you have to factor it.  Since it's a second degree polynomial, you'll have 2 solutions.  Factoring this using the quadratic formula, you'll get factors of (5x-8)(3x-4).  Solving these for x you get x = 8/5 and x = 4/3.
6 0
3 years ago
From a group of 6 candidates, a committee of 2 people is selected. In how many different ways can the committee be selected? I k
kolezko [41]
This is a combination problem. 

6 nCr 2

\frac{6!}{2! * (6-2)!} =  \frac{720}{48}=15<span><span>

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7 0
3 years ago
Read 2 more answers
Find the missing side length… please help
My name is Ann [436]

Answer:

  • So let's consider the triangle
  • \tan(46)  =  \frac{17}{x}
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7 0
3 years ago
An exceptionally bright high school student has applied for two scholarships: a merit scholarship and an athletic scholarship. H
9966 [12]

Answer:

a) 0.70

b) 0.82

Step-by-step explanation:

a)

Let M be the event that student get merit scholarship and A be the event that student get athletic scholarship.

P(M)=0.3

P(A)=0.6

P(M∩A)=0.08

P(not getting merit scholarships)=P(M')=?

P(not getting merit scholarships)=1-P(M)

P(not getting merit scholarships)=1-0.3

P(not getting merit scholarships)=0.7

The probability that student not get the merit scholarship is 70%.

b)

P(getting at least one of two scholarships)=P(M or A)=P(M∪A)

P(getting at least one of two scholarships)=P(M)+P(A)-P(M∩A)

P(getting at least one of two scholarships)=0.3+0.6-0.08

P(getting at least one of two scholarships)=0.9-0.08

P(getting at least one of two scholarships)=0.82

The probability that student gets at least one of two scholarships is 82%.

4 0
3 years ago
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