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3 years ago

What is the x intercept of the line 3x+2y-10=0

Mathematics

2 answers:

Margarita [4]3 years ago

6 0

3x+2y-10=0
3x=-2y+10 (divide both sides by 3)
X=-2/3 y +10/3

Vesna [10]3 years ago

5 0

To find the x int, sub in 0 for y and solve for x
3x + 2y - 10 = 0
3x + 2(0) - 10 = 0
3x - 10 = 0
3x = 10
x = 10/3.....so ur y int is 10/3 or (10/3,0)

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An equation of the line that passes through (3, 1) and (0, 10).

MrMuchimi

Answer:

So the equation of the line that passes through (3, 1) and (0, 10) is y=-3x+10

Step-by-step explanation:

(3, 1) and (0, 10)

m=y²-y¹/x²-x¹

m=10-1/0-3

m=9/-3

m=-3

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y-y=m(x-x1)

y-1=-3(x-3)

y-1=-3x+9

+1 +1

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3 years ago

What is quartile 1 (Q1)quartile 3 (Q3) and the IQR? Answer all three parts . 13, 23, 24, 25, 26, 26, 37, 47, 47, 48, 50

Fittoniya [83]

Answer:

Quartile 1 (Q1) = 24

Quartile 2 (Q2) = 47

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Step-by-step explanation:

Given:

The set of data are:

13, 23, 24, 25, 26, 26, 37, 47, 47, 48, 50

The data are in increasing order. The number terms are, $n = 11$ .

Therefore, the middle term = $\frac{n+1}{2}=\frac{11+1}{2}=6^{th}\ term$

So, the median = 26

Now, the median divides the set of data into two parts. The median of first part is the quartile 1 and the median of second part is quartile 2.

So, the first part has the following terms:

13, 23, 24, 25, 26

Here also, $n=5$ . So, the third term is the median.

∴ Q1 = 24

The second part has the following terms:

37, 47, 47, 48, 50

Here also, $n=5$ . So, the third term is the median.

∴ Q2 = 47.

Now, IQR = Q2 - Q1 = 47 - 24 = 23.

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When point A( 3, 1) is translated 2 units to the right and 6 units up the coordinates of point A'

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Answer:

A' = (5,7)

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In the same way, we move 6 units up... so we move along the Y-axis. We go up, so we also increase the value of y. Starting with y = 1, we move up by 6 units... so we are now at y = 7.

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