Differentiating an integral removes the integral.
f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
Answer:
22/3
Step-by-step explanation:
Make the whole number turn into a fraction, (21/3) and add the numerator (1/3), which the answer would be 22/3
3/2 because the proper solution is rise over run, in this case it rises 3 & runs to the right 2
Suppose y varies inversely with x and that y=2 when x=8 What is an equation for this inverse variation?
B. y= 2/8x
