I don't know if it's (1/x )+ 5 or 1/(x+5) anyways
g(x) = x-2 so in f(g(x)) you replace every x with x-2
f(g(x)) = (1/(x-2)) + 5 or 1/(x-2-5) = 1/(x-7)
if the function is like the first form so you avoid numbers which will make your denominator equals zero
x-2 = 0, x=2 or x-7 = 0, x=7
so if it's like first one answer is R - 2
if it's second answer is R - 7
Answer:
Here's my work for this problem:
We have given
hypotenuse=<span>6√2
let us suppose leg =a
using Pythagorean theorem
a^2+a^2=(</span><span>6√2)^2
</span>2a^2=36*2
diving by 2 on both sides
a^2=36
taking square root on both sides
√a^2 =<span>√36
a=6
therefore
</span><span>the leg of each isosceles right triangle is 6</span>
It would be in a radius between 6*200 and 8*200
Answer:
2x2 = 8x-3
4 = 8x - 3 | +3
7=8x
x=7/8
Step-by-step explanation:
