Answer:
you can do a trial and improvement
Step-by-step explanation:
The answer is 64,097,343,225
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Step-by-step explanation:
1. 1*1/6= 1 /6=1.67
2. 9*7/10= 63/10= 6.3
3. 7*4/8= 28/8= 3.5
4. 1/2 of 2= 1/2*2= 0.5*2= 1
5. 1/12 of 2= 1/12*2= 8.33*2= 16.66
6.2/6 of 2= 2/6*2= 3.33*2= 6.66
7. 1/3 of 5= 1/3*5= 3.33*5= 16.65
8. 3/10 of 8= 3/10*8= 0.3*8= 2.4
Hope it's help you ♥️
