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Angelina_Jolie [31]
3 years ago
8

Calculate the value for each determinant:

Mathematics
1 answer:
Dafna1 [17]3 years ago
4 0

Answer:

See explanations below

Step-by-step explanation:

Example of how to find the determinant of a 2×2 matrices is as shown;

\left[\begin{array}{ccc}a&b\\c&d&\end{array}\right]

= (a*d)-(b*c)

= ad - bc

Applying this to solve the given questions

1) (3*4) - (-3*-1)

= 12 - (3)

= 9

2) (-12*5)-(-1*12)

= -60 - (-12)

= -60+12

= -48

3) (0*4)-(-1*17)

= 0-(-17)

= 0+17

= 17

4) (8*-1)-(-4*-1)

= -8-(4)

= -8-4

= -12

5) (2*-1)-(2*-1)

= -2-(-2)

= -2+2

= 0

6) 1(1) - 0(0)

= 1 - 0

= 1

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Problem: 6x-3(2-3x)

<em>Let's solve!</em>

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To solve -3 = -19 + d/5, what steps would you use?
Pachacha [2.7K]

To solve the expression, the steps are add 19 and multiply by 5

<h3>How to solve the expression</h3>

Given the equation;

-3 = -19 + d/5

First,

Collect like terms

-3+ 19 = d/5

Add the values on the left side

We have

16 = d/5

Cross multiply

16 × 5 = d

We then have

d = 80

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1 year ago
What is the remainder when 19x^2 + 15x + 12 is divided by x - 2?
Aleksandr-060686 [28]

Answer:

R = 118

Step-by-step explanation:

Given

Represent the polynomial with P and the divisor with D

P = 19x^2 + 15x + 12

D = x -2

Required

Determine the remainder

We start by equating the divisor to 0

i.e.

D = 0

x - 2 = 0

x = 2

Substitute 2 for x in the polynomial.

This gives remainder (R)

R = 19*2^2 + 15*2 + 12

R = 19*4 + 15*2 + 12

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