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Angelina_Jolie [31]
3 years ago
8

Calculate the value for each determinant:

Mathematics
1 answer:
Dafna1 [17]3 years ago
4 0

Answer:

See explanations below

Step-by-step explanation:

Example of how to find the determinant of a 2×2 matrices is as shown;

\left[\begin{array}{ccc}a&b\\c&d&\end{array}\right]

= (a*d)-(b*c)

= ad - bc

Applying this to solve the given questions

1) (3*4) - (-3*-1)

= 12 - (3)

= 9

2) (-12*5)-(-1*12)

= -60 - (-12)

= -60+12

= -48

3) (0*4)-(-1*17)

= 0-(-17)

= 0+17

= 17

4) (8*-1)-(-4*-1)

= -8-(4)

= -8-4

= -12

5) (2*-1)-(2*-1)

= -2-(-2)

= -2+2

= 0

6) 1(1) - 0(0)

= 1 - 0

= 1

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Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : \text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. 13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130      (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. 9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270      (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups =\dfrac{\text{Sum of combined students}}{\text{combined students}}

=\dfrac{400}{40}=10

Hence, the average was 9 years old find the average age of both groups is 10 years old.

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Step-by-step explanation:

I hope I have helped you can you put that this is the smartest answer please?

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