6. Which of the following is equivalent to the expression shown?
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
The summary of the given statistics data include:
sample size n = 400
sample mean = 6.86
standard deviation = 4.37
Level of significance ∝ = 0.01
Population Mean = 6.00
Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
To start with the hypothesis;
The null and the alternative hypothesis can be computed as :
The test statistics for this two tailed test can be computed as:
z = 3.936
degree of freedom = n - 1
degree of freedom = 400 - 1
degree of freedom = 399
At the level of significance ∝ = 0.01
P -value = 2 × (z < 3.936) since it is a two tailed test
P -value = 2 × ( 1 - P(z ≤ 3.936)
P -value = 2 × ( 1 -0.9999)
P -value = 2 × ( 0.0001)
P -value = 0.0002
Since the P-value is less than level of significance , we reject at level of significance 0.01
Conclusion: There is sufficient evidence to conclude that the original claim that the mean of the population of earthquake depths is 5.00 km.
Answer:
The answer is " and
"
Step-by-step explanation:
Calculating the sum:
// 163+41=204
Explanation:
In the addition, first convert the given value (a,b) into decimal point that is (163, 41) and by adding its value is equal to (204) and after convert its value is equal to .
Calculating the product:
// 163 *41=6,683
Explanation:
In the product calculation we convert the given value (a,b) into decimal point that is (163, 41) and multiplting its value which is equal to (6,683) and after convert its value is equal to .