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hjlf
3 years ago
14

How many electrons does Sodium lose to become an ion

Chemistry
1 answer:
Genrish500 [490]3 years ago
4 0
For Sodium would need to lose 11 electrons to become an ion.
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Given a compound with a mw of 169 amu having 13.60% na, 8.29% n, 35.51% c, 4.77% h, and 37.85% o, determine the number of each a
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1) Percent composition

<span>Na: 13.60%,
N:     8.29%
C:    35.51%
H:      4.77%
O:   37.85%
     -------------
       100.02%

2) Convert mass percent to molar composition

For that, divide the percent of each element by its atomic mass.

</span>
<span>Na: 13.60 / 22.99 = 0.5916
N:     8.29 / 14.01 = 0.5917
C:    35.51 / 12.01 = 2.9567
H:      4.77 / 1.01 = 4.7228
O:   37.85 / 16.00 = 2.3656

3) Divide each number by the smallest one:

</span>
<span><span>Na:  0.5916 / 0.5916 = 1.0
N:     0.5917 / 0.5916 = 1.0
C:    2.9567 / 0.5916 = 5.0
H:      4.7228 / 0.5916 = 8.0
O:   2.3656</span> / 0.5916 = 4.0

4) State the empirical formula: Na N C5 H8 O4

5) Calculate the mass of the empirical formula:

Multiplicate the number of each atoms times the atomic mass corresponding atomic mass of the atom.

1 * 22.99 + 1 * 14.01 + 5 * 12.01 + 8 * 1.01 + 4 * 16.00 = 169.13

6) Divide the molar mass by the mass of the empirical formula:

169 / 169.13 = 1

7) Conclusion: the molecular formula is Na N C5 H8 O4, so the number of atoms present in the compound formula are:

Na: 1
N: 1
C: 5
N: 8
O: 4
</span>

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