The shape of an ammonia molecule is trigonal pyramidal (see the image below).
The N atom is at the top of the pyramid and the three H atoms are at the corners of a triangular base.
The mass of FeS formed : 11.97 g
<h3>Further explanation</h3>
Reaction
Fe(s) + S(s) → FeS(s)
mass Fe=7.62 g
mol Fe(MW=56 g/mol) :

mass S=8.67 g
mol S(MW=32 g/mol) :

Limiting reactant : smaller ratio(mol:coefficient) ⇒coefficient=1
Fe : S =0.136 : 0.271⇒Fe limiting(smaller), S excess
Mol FeS based on Fe , so mol FeS=0.136
Mass FeS(MW=88 g/mol) :

Answer:
In an electrophilic aromatic substitution (Friedel Crafts alkylation) first in the monoalkylation of the 1,4-dimethoxybenzenethe the methoxy groups redirects the substitution for ortho-para positions with respect to the electrophile that is going to enter (alkyl group) this is due to the increase in electron density in that position, that is , to the inductive effect.
According to the second incoming alkyl group there would be 3 positions available, from which it will choose the meta position in relation to the second methoxy group, since the alkyl group is a weak activator of the ortho meta positions and coincides with the position to which it redirects the second methoxy group.
1,2,3, or 4. Generally, carbon likes to make 4 bonds to 4 different atoms. For example, in methane(CH4), Carbon makes 4 bonds to 4 hydrogens. However, Carbon can also make double and triple bonds to atoms. This means that of the 4 bonds, more are used to bond to one thing. For example, in the compound CN, Carbon bonds to hydrogen on one side and triple bonds to Nitrogen on the other. This shows carbon can bond to at 2 atoms as well as 4 at a time. using a one double bond carbon would only bond to 3 atoms. I cant think of an example where carbon only bonds to one other atom without breaking the octet rule, but all the other values can be validated through examples. So, I still think the bottom answer is correct. Hope this helped!