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3 years ago

Which describes the role of oxygen in photosynthesis?

Chemistry

2 answers:

Nikitich [7]3 years ago

7 0

Answer:

it is a reactant so it enters the plant.

Explanation:

Basile [38]3 years ago

5 0

Photosynthesis is the process utilized in the chloroplasts of plant cells, where carbon dioxide and water undergo a chemical process with radiant energy, usually from the sun. The resulting products are energy stored in the form of a glucose molecule, and oxygen, which is given off as a waste product.

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How do transitional fossils fit with the theory of evolution

iren2701 [21]

These transitional fossils serve as evidence to Darwin's Theory of Natural Selection as conserved traits are proven to survive the test of time. This also supports evolution in a way that is shows gradual change in traits of species over generations due to change in living conditions.

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3 years ago

How many oxigen are need it to produce two moleculas of water molecules

emmainna [20.7K]

4 atoms of Oxygen are required to make 2 atoms of hydrogen. The compound H2O is 1 Hydrogen and 2 Oxygen.

7 0

3 years ago

Consider the equilibrium reaction. 4A+B↽−−⇀3C After multiplying the reaction by a factor of 2, what is the new equilibrium equat

disa [49]

8A+2B——> 6C
since you multiply by a factor of 2 you do that to each letter
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8 0

3 years ago

help me please. Can you please explain to me how to solve them? you can also send me a photo if that's better for you. thanks al

zheka24 [161]

Refer to the attachment

7 0

3 years ago

Kc for the reaction of hydrogen and iodine to produce hydrogen iodide.

tatiyna

Answer:

$[H_2]_{eq}=0.183M$

$[I_2]_{eq}=0.183M$

$[HI]_{eq}=0.025M$

Explanation:

Hello.

In this case, for this equilibrium problem, we first realize that at the beginning there is just HI, it means that the reaction should be rewritten as follows:

$2HI\rightleftharpoons H_2+I_2$

Whereas the law of mass action (equilibrium expression) is:

$Kc=\frac{[H_2][I_2]}{[HI]^2}$

That in terms of initial concentrations and reaction extent or change $x$ turns out:

$Kc=\frac{x*x}{([HI]_0-2x)^2}\\\\54.3=\frac{x^2}{(0.391M-2x)^2}$

And the solution via solver or quadratic equation is:

$x_1=0.183M\\\\x_2=0.210M$

Whereas the correct answer is 0.183 M since the other value yield a negative concentration of HI at equilibrium (0.391-2*0.210=-0.029M).This, the equilibrium concentrations are:

$[H_2]_{eq}=0.183M$

$[I_2]_{eq}=0.183M$

$[HI]_{eq}=0.391M-2*0.183M=0.025M$

Regards.

6 0

3 years ago