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Ostrovityanka [42]
3 years ago
14

A hydrogen filled balloon has a volume of 8.3 L at 36°C and 751 mmHg. How many moles of hydrogen are inside the balloon?

Chemistry
1 answer:
tamaranim1 [39]3 years ago
8 0

Answer: I think the formula is PV=nRT and I divide both sides by RT, but this is as far as I can get in my equation before I get stumped: (751 mm Hg) (8.3 L)/ (309 K) Can you help?

Explanation:

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Titanium has an HCP unit cell for which the ratio of the lattice parameters c/a is 1.58. If the radius of the Ti atom is 0.1445
Karolina [17]

The unit cell volume of the crystal is V_c = 9.9084*10^-^2^3 cm^3 / unit cell and the density of titanium is calculated as 4.71g/cm^3 while the literature value is 4.5 g/cm^3

Data;

  • radius = 0.1445 nm
  • c/a = 1.58
  • A = 46.88 g/mol

<h3>Unit Cell Volume</h3>

The unit cell volume can be calculated as

V_c = 6R^2c\sqrt{3}\\

let's substitute the values into the formula

V_c = 6 * (1.445*10^-^8)^2 * 1.58 8 * a * \sqrt{3} \\a = 2R\\V_c = 6 * (1.445*10^-^8)^2 * 1.58* 2 * 1.445*10^-^8 * \sqrt{3}\\ V_c = 9.984*10^-^2^3 cm^3 / unit cell

The unit cell volume of the crystal is V_c = 9.9084*10^-^2^3 cm^3 / unit cell

<h3>Density of Ti</h3>

The density of titanium can be calculated as

\rho = \frac{nA}{V_c N_a}

  • n = 6 for hcp
  • A = 46.88 g/mol
  • Na = Avogadro's number

let's substitute the values into the formula

\rho = \frac{nA}{V_c Na}\\ \rho = \frac{6*46.88}{9.9084*10^-^2^3* 6.023*10^2^3} \\\rho = 4.71 g/cm^3

The density of titanium is calculated as 4.71g/cm^3 while the literature value is 4.5 g/cm^3

Learn more on crystal lattice here;

brainly.com/question/6610542

8 0
2 years ago
The density of mercury is 13.6 g/cm3, What is its density in mg/mm3?
forsale [732]

Answer:

Density of mercury is 13600 kg

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3 years ago
10.How do you make sure there is no cross contamination of your samples of<br> substances?
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Have a clean workspace, always wear clean gloves, never reuse or leave Lab wearing gloves, sanitize!
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The uppermost layer of the atmosphere
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4 0
3 years ago
Read 2 more answers
Limiting Reactant Worksheet
faltersainse [42]

Answer:

a) 1.61 mol

b) Al is limiting reactant

c) HBr is in excess

Explanation:

Given data:

Moles of Al = 3.22 mol

Moles of HBr = 4.96 mol

Moles of H₂ formed = ?

What is limiting reactant =

What is excess reactant = ?

Solution:

Chemical equation:

2Al  + 2HBr  → 2AlBr + H₂

Now we will compare the moles:

                Al              :               H₂

                  2              :               1

                 3.22         :            1/2×3.22 = 1.61 mol

                HBr            :              H₂

                 2                :               1

                4.96            :          1/2×4.96 = 2.48 mol      

The number of moles of H₂ produced by Al are less it will be limiting reactant while HBr is present in excess.

Moles of H₂ :

Number of moles of H₂ = 1.61 mol

6 0
3 years ago
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