Answer: 23, 25, 27
Step-by-step explanation:
Let the 3 consecutive odd numbers be x, x+2 and x+4.
So
2x+(x+2)+3(x+4)=152
2x + x + 2 + 3x + 12 = 152
6x+14=152
6x = 152 - 14
x=138/6
x=23
So, the numbers are 23, 25 and 27.
Answer:
495 combinations of 4 students can be selected.
Step-by-step explanation:
The order of the students in the sample is not important. So we use the combinations formula to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
How many combination of random samples of 4 students can be selected?
4 from a set of 12. So
495 combinations of 4 students can be selected.
you start at the origin and go down 4 right 1. So the range is 4 and the domain is x
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let <em>A</em> be the event of getting an odd number.
<em>P(A)</em> be the probability of getting an odd number.
Total odd numbers here are 6 i.e.
Here, total numbers in the game are 12 i.e .
Formula for probability of an <em>event E</em> can be observed as:
Let <em>B</em> be the event of getting 11.
<em>P(B)</em> be the probability of getting 11.
Total number of possible cases is 1.
is the probability that we get 11 and an odd number.
Possible number of cases = 1
<em>P(B/A)</em> is the probability that we get an 11 given that it is an odd number.
Hence, P(B/A) =
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