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Alexeev081 [22]

1 year ago

5

Suppose that a>1/2 and the parabola with equation y=ax^2+2 has vertex V. The parabola intersects the line with equation y=-x+

4a at points B and C, as shown. If the area of triangle VBC is 72/5, determine the value of A.

1 answer:

suter [353]1 year ago

7 0

Answer:

Y = ×+ 4 a 75 VBC

I HOPE ITS HELP

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2 years ago

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3 years ago

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3 years ago

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