Suppose that a>1/2 and the parabola with equation y=ax^2+2 has vertex V. The parabola intersects the line with equation y=-x+
4a at points B and C, as shown. If the area of triangle VBC is 72/5, determine the value of A.
1 answer:
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<h3>hello!</h3>
We're given a point that the line intersects and its slope.
Let's use Point-slope:-
y1 = -5
m=-5
x1=-1
Convert to slope-intercept:-
Finally,
Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)
