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Mashcka [7]
2 years ago
6

The blue segment below is a diameter of OO. What is the length of the radius of the circle? O A. 2.95 units O B. 11.8 units O c.

5.9 units O D. 8.85 units​

Mathematics
1 answer:
Archy [21]2 years ago
6 0

Answer:

The length of the radius is <u><em>2.95 units </em></u>

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Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work
valina [46]

Answer:

Step-by-step explanation:

Question

Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.​

perimeter of a triangle = AB+AC+BC

Using the distance formula

AB = sqrt(-2-5)²+(2-2)²

AB = sqrt(-7)²

AB =sqrt(49)

AB =7

BC = sqrt(-2+2)²+(2-5)²

BC = sqrt(0+3²)

BC =sqrt(9)

BC =3

AC= sqrt(-2-5)²+(2-5)²

AC= sqrt(-7)²+3²

AC =sqrt(49+9)

AC =sqrt58

Perimeter = 10+sqrt58

5 0
2 years ago
Lori wants to determine the average amount of time that students at her school spend on a computer each day there are 350 studen
Bezzdna [24]

Answer:

2 students from each 15 classrooms

Step-by-step explanation:

"The number of boys and girls is approximately equal" is probably the most random sample, that is if the whole topic of the publication is Lorrie and her experimenting endeavors. If that is not the subject, then "Lorrie wants to determine the average amount of time that students at her school spend on the computer each day" is the most strange and random

3 0
3 years ago
Factor completely 6x^2 -4x
Liono4ka [1.6K]

Answer:

2x(3x−2)

Step-by-step explanation:

Factor 6x^{2} − 4x

6x^{2} − 4x

=2x(3x−2)

Hope this helps!

4 0
2 years ago
Lim x-1 x2 - 1/ sin(x-2)
balu736 [363]

Answer:

           \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0

Explanation:

Assuming the correct expression is to find the following limit:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}

Use the property the limit of the quotient is the quotient of the limits:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}

Evaluate the numerator:

          \frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}

Evaluate the denominator:

  • Since         \lim_{x \to1}sin(x-2)\neq 0

                  \frac{0}{\lim_{x \to1}sin(x-2)}=0

4 0
3 years ago
What is the altitude of a rhombus if its area is 10 square meters and the length on one side is 2.5 meters?
Elan Coil [88]
10/2.5= 4 the answer is 4 meters because you just divide them. 

4 0
3 years ago
Read 2 more answers
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