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horrorfan [7]
3 years ago
8

How to solve this question

Mathematics
1 answer:
Fiesta28 [93]3 years ago
4 0
7 = 5y - 3
add 3 to both sides
10 = 5y
divide both sides by 5
2 = y
-1 = 5y - 3
add 3 to both sides
2 = 5y
divide bothe sides by 5
2/5 = y
-3 = 5y - 3
add 3 to both sides
0 = 5y
divide both sides by 5
0 = y
6 = 5y - 3
add 3 to both sides
9 = 5y
divide both sides by 5
9/5 = y
-8 = 5y - 3
add 3 to both sides
-5 = 5y
divide both sides by 5
-1 = y
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julsineya [31]
B. healthy financial choices
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3 years ago
Read 2 more answers
I dont understand I need help
gregori [183]

Answer:

7.4825 km or 7.48 km (rounded to nearest hundredth)

Step-by-step explanation:

<u>Ranch's measurements rounded up to the nearest hundredth:</u>

1st measurement = \sqrt{60} = 7.75 km

2nd measurement = \frac{58}{8} = 7.25 km

3rd measurement = 7.3(recurring) = 7.33 km

4th measurement = 7\frac{3}{5} = 7.60

<u>The average of the four measurements is:</u>

(7.75 + 7.25 + 7.33 + 7.60) ÷ 4 = 7.4825 km or 7.48 km (rounded to nearest hundredth)

6 0
3 years ago
Please answer thank you
mafiozo [28]

Answer:

D. Zero

Step-by-step explanation:

A solution is formed when the lines intersect at a

point. The coordinates will then be the solution.

In the diagram shown, the line and curve does not intersect at all so there is no solution to the curve.

7 0
3 years ago
39-50 find the limit.<br> 41. <img src="https://tex.z-dn.net/?f=%5Clim%20_%7Bt%20%5Crightarrow%200%7D%20%5Cfrac%7B%5Ctan%206%20t
Katyanochek1 [597]

Write tan in terms of sin and cos.

\displaystyle \lim_{t\to0}\frac{\tan(6t)}{\sin(2t)} = \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)}

Recall that

\displaystyle \lim_{x\to0}\frac{\sin(x)}x = 1

Rewrite and expand the given limand as the product

\displaystyle \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)} = \lim_{t\to0} \frac{\sin(6t)}{6t} \times \frac{2t}{\sin(2t)} \times \frac{6t}{2t\cos(6t)} \\\\ = \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right)

Then using the known limit above, it follows that

\displaystyle \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right) = 1 \times 1 \times \frac3{\cos(0)} = \boxed{3}

4 0
1 year ago
What does f(3) means ?
Butoxors [25]

F(x)=x^2+x+5  

then  

F(3) would be the function evaluated at x=3, or 17.

anytime you see F(3) it is just whatever formula you are looking at evaluated when the variable is equal to 3.

5 0
3 years ago
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