Answer:
3
Step-by-step explanation:
combine like terms (so 1/2 and 3/2): 2 - x = x - 4
add x to both sides: 2 = 2x - 4
add 4 to both sides: 6 = 2x
divide both sides by 2: 3 = x
1. Given that e<span>vents A and B are dependent, P(A)=20%, P(BIA)=25%. What is P(A and B)?
P(BIA)=[P(A and B)]/P(A)
it follows then that:
P(A and B)=P(A)*P(BIA)
P(A)=0.2
P(BIA)=0.25
hence
P(A and B)=0.2*0.25=0.05=5%
2. Given that </span><span> P(A) =12%, P(B)=48% and P(A or B)=50%. What is P(A and B)?
P(A or B)=P(A)+P(B)-P(A and B)
but
P(A)=12%, P(B)=48%, P(A and B)=50%
thus
P(A or B)=12%+48%-50%
simplifying the above we obtain:
P(A or B)=60%-50%=10%
</span>
Answer:
1. 0.6
2. 14/25
3. 561%
4. 0.0032
5. 0.274
Step-by-step explanation:
<span>Winning Probablity = 0.2, hence Losing Probability = 0.8
Probablity of winning atmost one time, that means win one and lose four times or lose all the times. So p(W1 or W0) = p (W1) + p(W0)
Winning once W1 is equal to L4, winning zero times is losing 5 times.
p(W1) = p(W1&L4) and this happens 5 times; p(W0) = p(L5);
p (W1) + p(W0) = p(L4) + p(L5)
p(L4) + p(L5) = (5 x 0.2 x 0.8^4) + (0.8^5) => 0.8^4 + 0.8^5
p(W1 or W0) = 0.4096 + 0.32768 = 0.7373</span>
Answer:
if give brainliest i will answer
Step-by-step explanation:
