Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
Given:
Figures A, B and C.
To find:
The order of the figures and volume of each figure.
Solution:
<u>Figure A:</u>
Length = 10, Width = 2 and Height = 2
Volume of A = length × width × height
= 10 × 2 × 2
Volume of A = 40 cubic units
<u>Figure B:</u>
Length = 3, Width = 3 and Height = 1
Volume of B = length × width × height
= 3 × 3 × 1
Volume of B = 9 cubic units
<u>Figure C:</u>
Length = 6, Width = 3 and Height = 3
Volume of C = length × width × height
= 6 × 3 × 3
Volume of C = 54 cubic units
Order from greatest to least:
54 < 40 < 9
C < A < B
Hence Kurry said the correct answer.
Square Perimeter = 4(4x-1)
Rectangle Perimeter = 2(2x+1) + 2(x+2)
Square Perimeter = Rectangle Perimeter
4(4x-1) = 2(2x+1) + 2(x+2)
16x - 4 = 4x + 2 + 2x + 4
16x - 4 = 6x + 6
-6x +4 -6x +4
10x = 10
x = 1
Your gonna divide 72 by 2 so therefore you get 36
So that equals to Nicole’s age
