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3 years ago

12.2 - N =3.3 i need heeeeelpXD

2 answers:

6 0

Remember you can do ANTYHING to an equation as long asyou do it to both sides

12.2-N=3.3
minus 3.3 both sides
12.2-3.3-N=3.3-3.3
8.9-N=0
add N to both sides
8.9+N-N=0+N
8.9+0=N
8.9=N

Sergeu [11.5K]3 years ago

5 0

If you do 12.2-3.3 youll get your answer

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cupoosta [38]

Answer:

$t=(15-1) [\frac{0.219}{0.2}]^2 =16.7864$

$p_v = 2*P(\chi^2_{14}>16.786)=0.5355$

And the 2 is because we are conducting a bilateral test.

$\alpha=0.05$ since the the $p_v >0.05$ we fail to reject the null hypothesis.

$\alpha=0.01$ since the the $p_v >0.01$ we fail to reject the null hypothesis.

Step-by-step explanation:

Data given

$\mu=7$ population mean (variable of interest)

$\sigma=0.2$ represent the population standard deviation

$s=0.219$ represent the sample deviation

n=15 represent the sample size

$\alpha=0.05,0.01$ represent the values for the significance level

Hypothesis test

On this case we want to check if the population standard deviation is equal or not to 0.2, so the system of hypothesis are:

H0: $\sigma = 0.2$

H1: $\sigma \neq 0.2$

In order to check the hypothesis we need to calculate the statistic given by the following formula:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

This statistic have a Chi Square distribution distribution with n-1 degrees of freedom.

What is the value of your test statistic?

Now we have everything to replace into the formula for the statistic and we got:

$t=(15-1) [\frac{0.219}{0.2}]^2 =16.7864$

P value

We know the degrees of freedom of the distribution 14 on this case and we can find the p value like this:

$p_v = 2*P(\chi^2_{14}>16.786)=0.5355$

And the 2 is because we are conducting a bilateral test.

$\alpha=0.05$ since the the $p_v >0.05$ we fail to reject the null hypothesis.

$\alpha=0.01$ since the the $p_v >0.01$ we fail to reject the null hypothesis.

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Substitute:

$y-(-7)=\dfrac{2}{5}(x-(-4))\\\\y+7=\dfrac{2}{5}(x+4)$

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