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emmainna [20.7K]
3 years ago
9

How can I solve for the logarithm?

Mathematics
1 answer:
Sergio039 [100]3 years ago
7 0
\bf 12^{2x-8}=15\\\\
-----------------------------\\\\
log_{{  a}}\left( x^{{  b}} \right)\implies {{  b}}\cdot  log_{{  a}}(x)\impliedby thus\\\\
-----------------------------\\\\
log\left( 12^{2x-8} \right)=log(15)\implies (2x-8)log(12)=log(15)
\\\\\\
2x-8=\cfrac{log(15)}{log(12)}\implies 2x=\cfrac{log(15)}{log(12)}+8\implies 
x=\cfrac{\frac{log(15)}{log(12)}+8}{2}
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