A. Yes you are correct that the gradient at any point is 3/(3x-1). However at point P it would be 3/(3*2-1)=2/5
b. The gradient of the normal would therefore be -5/2
We can use the general formula of an equation to get y-ln(5)=-5/2 (x-2)
Now multiply both sides by 2 to get:
2y-2ln(5)=-5x+10
Now when it crosses the x axis we know that y=0 therefore:
5x=10+2ln(5)
Therefore:
x=2+2/5 ln(5) when y=0
You could find an estimate of this number to be 2.64 (3sf) but this might not be sufficient
Answer:
A9.5
Step-by-step explanation:
I used a calculator......hope it helped:)))))))))))
Answer:
230
Step-by-step explanation:
sorry but the explanation is big and confusing i can't do the math step by step.
Linear equations can be written in the form <em>y = mx + b</em> where the multiplier "m" represents the slope of the line.
The linear equation <em>y = -8x + 6</em> has a slope equal to 3.
An image providing where the slope of the line is in y = mx + b is provided.