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sertanlavr [38]
3 years ago
10

Write the equation in slope intercept form. (-3, 1) and (-2, 0)

Mathematics
1 answer:
andre [41]3 years ago
6 0
Use the slope formula and slope-intercept form y=mx+b to find the equation.

Answer:
y=−1/5x + 2/5
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I will give brainliest and thank you to whoever helps/answers this
Neko [114]

Answer:

0 0 6

0 6 0

6 0 0

Step-by-step explanation:

Simple place value

5 0
3 years ago
I don’t know if i got the answer wrong but help!
Gwar [14]

Answer:

skew

Step-by-step explanation:

Perpendicular lines must intersect. In fact, they intersect forming right angles.

Lines AC and RC are not in the same plane and do not intersect.

They are called "skew lines."

4 0
3 years ago
Read 2 more answers
Which equation represents an exponential function with the initial value of 500?
EastWind [94]

Answer:

A exponential equation is usually of the form f(x)=a (1±r)ˣ.

Our limitation: Initial Vale is 500.

Let's look at our options:

#1- Initial Value of 1000  --- WRONG!

#2- Initial Value of 1000  --- WRONG!

#3- Initial Value of 500 ---- Maybe

#4- Initial Value of 500 ---- Maybe

Let's look at 3 and 4:

#3- Fits Our Form of f(x)=a (1±r)ˣ ---- CORRECT!

#4- Does not fit Our Form of f(x)=a (1±r)ˣ, It's to the 2nd power, not the x power! ---- WRONG!

Hence, #3 Is correct!

Step-by-step explanation:

Well, I hope you understood, and I'd gladly explain anything that didn't make sense. A brainliest would be appreciated, thank you!

-Zylynn Jade Ardenne

5 0
2 years ago
What are the correct answers and why? Simple and concise explanation please!!!
dezoksy [38]

Answer:

\large\boxed{-\bigg[(x-3)^2+2x\bigg]+1}\\\\\boxed{-x^2+4x-8}

Step-by-step explanation:

(g\ \circ\ f)(x)=g\bigg(f(x)\bigg)

f(x)=(x-3)^2+2x\\\\g(x)=-x+1\\\\g\ \circ\ f\to\text{put f(x) instead of x in the function g(x)}:\\\\(g\ \circ\ f)(x)=-\bigg[\underbrace{(x-3)^2+2x}_{x}\bigg]+1

-----------------------------------------

-\bigg[(x-3)^2+2x\bigg]+1=-(x-3)^2-2x+1\\\\\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\=-(x^2-(2)(x)(3)+3^2)-2x+1=-(x^2-6x+9)-2x+1\\\\=-x^2-(-6x)-9-2x+1=-x^2+6x-9-2x+1\\\\\text{combine like terms}\\\\=-x^2+(6x-2x)+(-9+1)=-x^2+4x-8

-----------------------------------

-x^2+4x-8=-x^2+4x-2^2+2^2-8=-(x^2-4x+2^2)+4-8\\\\=-(\underbrace{x^2-(2)(x)(2)+2^2}_{(a-b)^2=a^2-2ab+b^2})-4=-(x-2)^2-4=-(x+1-3)^2-4

In\ (-x+1-3)^2+2x,\ x^2\ will\ be\ positive.\\In\ (-x+1-3)^2+2(-x+1),\ x^2\ will\ be\ positive.

6 0
3 years ago
Read 2 more answers
Sadie computes the perimeter of a rectangle by adding the length, l , and width, w , and doubling this sum. Eric computes the pe
larisa [96]

a) P = 2(l+w)  Sadie

 P =2l+2w  Eric

b)  Sadie : P = 2(30+75) = 2(105) = 210

Eric: P = 2(30) +2(75) = 60+150 =210

4 0
3 years ago
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