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Reil [10]
3 years ago
5

Help me plz i am very confused

Mathematics
1 answer:
sesenic [268]3 years ago
3 0
I can't read that.... Sorry
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Is (A) correct or no????
Maslowich

Answer:

no

Step-by-step explanation:

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3 years ago
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I need help with this question!!
Veronika [31]

Answer:

right

Step-by-step explanation:

4 0
3 years ago
Find the equation of the line which is parallel to y = 4x + 3 and goes through the point (4, 5)​
skad [1K]

Answer:

  • y = 4x - 11

Step-by-step explanation:

The given line has a slope m = 4.

We know parallel lines have equal slopes.

<u>Use point - slope equation and substitute the coordinates of the given point to get:</u>

  • y - 5 = 4(x - 4)
  • y - 5 = 4x - 16
  • y = 4x - 16 + 5
  • y = 4x - 11
7 0
3 years ago
Find the tangent plane to the given surface of f(x,y)=6- 6/5 x-y at the point (5, -1, 1). Make sure tat your final answer for th
HACTEHA [7]

Answer:

Required equation of tangent plane is z=\frac{6}{5}(x-5y-11).

Step-by-step explanation:

Given surface function is,

f(x,y)=6-\frac{6}{5}(x-y)

To find tangent plane at the point (5,-1,1).

We know equation of tangent plane at the point $(x_0,y_0,z_0)[/tex] is,

z=f(x_0,y_0)+f_x(x_0,y_0)(x-x_0)+f_y(x_0,y_0)(y-y_0)\hfill (1)

So that,

f(x_0,y_0)=6-\frac{6}{5}(5+1)=-\frac{6}{5}

f_x=-\frac{6}{5}y\implies f_x(5,-1,1)=\frac{6}{5}

f_y=-\frac{6}{5}x\implies f_y(5,-1,1)=-6

Substitute all these values in (1) we get,

z=\frac{6}{5}(x-5)-6(y+1)-\frac{6}{5}

\therefore z=\frac{6}{5}(x-5y-11)

Which is the required euation of tangent plane.

4 0
3 years ago
Help me if you understand thanks sm
kumpel [21]
First, find the slope of the line using the formula for slope:

m = (y2 - y1) / (x2 - x1)

m = (4 - (-2)) / (-3 - 2) = -6/5

Then, use the point-slope formula using a point that you were given and the slope that you calculated.

y - y1 = m(x - x1)

y - 4 = (-6/5)(x + 3)

Then, simply get y alone.

y = (-6/5)x + 2/5
3 0
2 years ago
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