This question not incomplete
Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
0 - 10x + 1.5
Step-by-step explanation:
-2(5x - 0.75)
Expand the bracket
-10x + 1.5
0 - 10x + 1.5 is the equivalent expression
Answer: Hello! I believe your answer would be 162.
Step-by-step explanation: So the formula for Area on a rectangle is WxL. So length will be 9. But if you notice on the scale rectangle the width is the length times two. So the length on the real garden is 18.
Answer: I think the answer might be 225 but I'm not sure I'm 100% percent correct
