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2 years ago

I need help fast I appreciate it fam

Mathematics

1 answer:

Vanyuwa [196]2 years ago

5 0

I think the answer is 12.9

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HURRRYYY!!!<br> Which relation is a function?

Anna71 [15]

Answer:

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d is the answer

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3 years ago

PLEASE HELP I'M STUCK ;-;

QveST [7]

Answer:

the distributive property is supposed to simplify your equation

Step-by-step explanation:

-4.2 - 6y + 3.6

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2 years ago

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A golfer hits a ball from a starting elevation of 2 feet with a velocity of 70 feet per second down to a green with an elevation

ikadub [295]

Answer:

4.50 s

Step-by-step explanation:

The motion of the ball is represented by the following equation:

$h(t) = 2+70t-16t^2$ (1)

where

h(t) is the elevation at time t

2 ft is the initial elevation at t = 0

+70 ft/s is the initial vertical velocity

$-32 ft/s^2$ is the acceleration due to gravity

The green is located at an elevation of -7 feet, so the ball lands on the green when

h(t) = -7

Substituting into (1)

$-7=2+70t-16t^2$

And re-arranging we get

$16t^2-70t-9=0$

This is a second-order equation in the form

$at^2+bt+c=0$

which has solutions

$t_{1,2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ (2)

Here we have:

a = 16

b = -70

c = -9

Substituting into (2) we find the solutions:

$t_{1,2}=\frac{70\pm \sqrt{(-70)^2-4(16)(-9)}}{2(16)}$

The two solutions are:

t = 4.50 s

t = -0.125 s

The second solution is negative, and since negative time has no physical meaning, the only correct solution is

t = 4.50 s

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3 years ago

50 POINTS !!<br><br><br> PLEASE HELP AND EXPLAIN !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.

allochka39001 [22]

I need the point my point is -

4 0

3 years ago

Read 2 more answers

Type the correct answer in each box.

Mariulka [41]

Answer:

$(x-5)^2+(y+4)^2=100$

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The distance between the center and any point that lie on the circle is equal to the radius

we have the points

(5,-4) and (-3,2)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

substitute the values

$r=\sqrt{(2+4)^{2}+(-3-5)^{2}}$

$r=\sqrt{(6)^{2}+(-8)^{2}}$

$r=\sqrt{100}\ units$

$r=10\ units$

step 2

Find the equation of the circle

we know that

The equation of a circle in standard form is equal to

$(x-h)^2+(y-k)^2=r^2$

where

(h,k) is the center

r is the radius

we have

$(h,k)=(5,-4)\\r=10\ units$

substitute

$(x-5)^2+(y+4)^2=10^2$

$(x-5)^2+(y+4)^2=100$

6 0

3 years ago