3 years ago

I need help fast I appreciate it fam

Mathematics

1 answer:

Vanyuwa [196]3 years ago

5 0

I think the answer is 12.9

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The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20. Each d

liberstina [14]

Answer: 0.0516

Step-by-step explanation:

Given : The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of $\lambda=20$ .

The probability mass function for Poisson distribution:- $P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}$

For x= 15 and $\lambda=20$ , we have

$P(X=x)=\dfrac{e^{-20}(20)^{15}}{15!}=0.0516488535318\approx0.0516$

Hence, the probability that exactly 15 defective components are produced in a particular day = 0.0516

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Add -8 + (-1)= <br> -7 <br> -9 <br> 9 <br> 7

sergejj [24]

Answer:

-9

hope it helped and stay safe

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LekaFEV [45]

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TiliK225 [7]

3/5 would be the answer because every 3 banana nut here is 5 corn

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