Question

b}{a+2b} = \frac{4}{3}" alt="\frac{a-3b}{a+2b} = \frac{4}{3}" align="absmiddle" class="latex-formula">

what is the value of a:b??

Answer 1

Answer:

$a:b = -17:1$

Step-by-step explanation:

Given

$\frac{a-3b}{a+2b} = \frac{4}{3}$

Required

Find a:b

$\frac{a-3b}{a+2b} = \frac{4}{3}$

Cross Multiply

$3(a-3b) = 4(a+2b)$

Open brackets

$3a - 9b = 4a + 8b$

Collect Like Terms

$3a - 4a = 8b+9b$

$-a = 17b$

Divide through by -b

$\frac{-a}{-b} = \frac{17b}{-b}$

$\frac{a}{b} = \frac{17}{-1}$

$\frac{a}{b} = \frac{-17}{1}$

Represent as a ratio

$a:b = -17:1$