Answer:
64√2 or 64 StartRoot 2 EndRoot
Step-by-step explanation:
A 45-45-90 traingle is a special traingle. Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem. Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2. 2(x)^2=c^2. You then square root both sides and get c= x√2.
Therefore, the two legs are x and the hypotenuse is x√2. x√2=128 because the question says that the hypotenuse is 128. Solve for x by dividing both sides by √2. X=128/√2. You rationalize it by multiplying the numberator and denominator of the fraction by √2. √2*√2= 2.
X=(128√2)/2= 64√2 cm.
Since X is the leg, the answer would be 64√2
x= 90° - 63° = 27° (NO perpendicular to AOB)
angle DOB = (90°+90°) -128° (angles on a straight line)
= 180° - 128°
= 52°
y= 180° - x - 63° - angle DOB (angles on a straight line)
=180° - 27° - 63° - 52°
= 38°
I'm not sure of the answer tho^^ good luck!
Well maybe because the only thing that is different is the - and +
B) y = 4x
X| * |Y|
2|2*4|8 |
3|3*4|12|
4|4*4|16|
5|5*4|20|
Answer:
i guess its linear pair type questions
i have done like this
