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Digiron [165]
3 years ago
11

how do I get help answering math problems showing how to figure them out

Mathematics
1 answer:
Veronika [31]3 years ago
7 0

Answer:

HI

Step-by-step explanation:

HI HI HI HI HI HI HI HI HI HI HI HI

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Problems with Equations: Mastery Test
GaryK [48]

Step-by-step explanation:

The answer is 8

Because you have to put each value of x given in the equation 3x = 24

So when you put the value 8

3(8) = 24

24 = 24

6 0
4 years ago
Sumita is following this recipe to make flapjacks.
Alexus [3.1K]

Answer:

20 flapjacks is the answer.

8 0
3 years ago
Write a rule describing the results when one multiplies three positive and negative decimals and changes the order of multiplica
anygoal [31]

Answer:

2 positive * 1 negative = negative

2 negative * 1 positive = positive

Step-by-step explanation:


one positive and 2 negative

(+ * -) * - =

positive times negative = negative * negative = positive

(+ * -) * -  = +

now if we change the order by putting parenthesis

+ *( - * -)

negative time negative = positive

+ * (+) = positive

the result is positive


The result does not change because of where we put the parentheses.


- * + * + =

negative  times positive = negative

negative * positive= negative

- * + * + =  negative

The order does not matter

6 0
3 years ago
Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.
suter [353]

Answer:

\theta = 30^\circ, 330^\circ

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

Step-by-step explanation:

Given [Missing from the question]

Equation:

cos\theta = \frac{\sqrt 3}{2}

Interval:

0 \le \theta \le 360

0 \le \theta \le 2\pi

Required

Determine the values of \theta

The given expression:

cos\theta = \frac{\sqrt 3}{2}

... shows that the value of \theta is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

cos\theta = \frac{\sqrt 3}{2}

Take arccos of both sides

\theta = cos^{-1}(\frac{\sqrt 3}{2})

\theta = 30 --- In the first quadrant

In the fourth quadrant, the value is:

\theta = 360 -30

\theta = 330

So, the values of \theta in degrees are:

\theta = 30^\circ, 330^\circ

Convert to radians (Multiply both angles by \pi/180)

So, we have:

\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}

\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}

\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

8 0
3 years ago
Write down the general equation of the normal distribution
Talja [164]

The following is the plot of the normal percent point function. where \phi is the cumulative distribution function of the standard normal distribution and Φ is the probability density function of the standard normal distribution.

8 0
3 years ago
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