Hey there! I'm happy to help!
To find the distance between two points, you square the difference of the x-values and square the difference of the y-values, add them, and then you square root it!
First, we'll add our two x-values.
-6-0= -6
We square it, which means to multiply it by itself.
-6(-6)=36 (If you multiply an even number of negative numbers, your answer is positive. Since we have two negative numbers, we get positive 36)
Now, we do the same with the y-values.
-2-(-1)=-1 (two negatives make it a plus, as in minus minus 1 is plus one.)
We square it.
-1(-1)=1
Now, we add these x and y value differences.
36+1=37
Now, we find the square root using a calculator.
√37≈6.08
Have a wonderful day!
Answer:
2x-3>15 and 3-7x>17 =
3-7x>17
-7x>14
x<-2
Step-by-step explanation:
Sorry this is not a proper equation. I think you meant this equation.
2x-3>15 and 3-7x>17
for this equation the answer is
3-7x>17
-7x>14
x<-2
Answer: 2+2=4 lol
Step-by-step explanation:
1+1=2
2+2=4
Answer:
12
Step-by-step explanation:
Answer:
![\frac{\sqrt[4]{3x^2} }{2y}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%20%7D%7B2y%7D)
Step-by-step explanation:
We can simplify the expression under the root first.
Remember to use 
Thus, we have:
![\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}} \\=\sqrt[4]{\frac{3x^{2}}{16y^{4}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B24x%5E%7B6%7Dy%7D%7B128x%5E%7B4%7Dy%5E%7B5%7D%7D%7D%20%5C%5C%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%7D)
We know 4th root can be written as "to the power 1/4th". Then we can use the property 
<em>So we have:</em>
<em>![\sqrt[4]{\frac{3x^{2}}{16y^{4}}} \\=(\frac{3x^{2}}{16y^{4}})^{\frac{1}{4}}\\=\frac{3^{\frac{1}{4}}x^{\frac{1}{2}}}{2y}\\=\frac{\sqrt[4]{3x^2} }{2y}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%7D%20%5C%5C%3D%28%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%5C%5C%3D%5Cfrac%7B3%5E%7B%5Cfrac%7B1%7D%7B4%7D%7Dx%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2y%7D%5C%5C%3D%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%20%7D%7B2y%7D)
</em>
<em />
<em>Option D is right.</em>
