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2 years ago

1.5 x 0.41Help with work

Mathematics

2 answers:

Murljashka [212]2 years ago

5 0

0.615 is the answer for this. All you gotta do is multiply or stick it in a calculator

andriy [413]2 years ago

3 0

Answer:

1.5x0.41=2.091 that the answer

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A ball is kicked 4 feet above the ground with an initial vertical velocity of 51 feet per second. The function h(t)=−16t²+51t+4

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Answer:

0.6 seconds to 2.6 seconds

Step-by-step explanation:

From the graph the ball reaches 28 feet after 0.574 seconds

and doesn't fall below that until 2.614 seconds

0.574 rounded is 0.6 seconds

2.614 rounded is 2.6 seconds

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3 years ago

Solve 2(x-3)>-3(-3+x) (Picture added, multiple choice)

Rudiy27

Answer:

Answer: D

Step-by-step explanation:

$2(x - 3) \geqslant - 3( - 3 + x)$

open the brackets [ distributive property ]

$2x - 6 \geqslant 9 - 3x$

collect like terms:

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3 years ago

In a recent study of 35 ninth-grade students, the mean number of hours per week that they played video games was 16.6. The stand

Mariulka [41]

Answer:

a) 16.6

b) The 95% confidence level of the mean of the time playing video games is between 15.7 and 17.5 hours.

c) The 99% confidence level of the mean of the time playing video games is between 15.4 and 17.8 hours.

d) The margin of error increases as the confidence level increases, due to the value of z, which means that the 99% confidence interval is larger.

Step-by-step explanation:

a. Find the best point of estimate of the population mean

The best estimate for the population mean is the sample mean, which is 16.6

b. Find the 95% confidence level of the mean of the time playing video games

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96\frac{2.8}{\sqrt{35}} = 0.9$

The lower end of the interval is the sample mean subtracted by M. So it is 16.6 - 0.9 = 15.7 hours

The upper end of the interval is the sample mean added to M. So it is 16.6 - 0.9 = 17.5 hours

The 95% confidence level of the mean of the time playing video games is between 15.7 and 17.5 hours.

c. Find the 99% confidence interval of the mean time playing video games

Following the same logic as above, we have that $Z = 2.575$ . So

$M = 2.575\frac{2.8}{\sqrt{35}} = 0.9$

The lower end of the interval is the sample mean subtracted by M. So it is 16.6 - 1.2 = 15.4 hours.

The upper end of the interval is the sample mean added to M. So it is 16.6 + 1.2 = 17.8 hours.

The 99% confidence level of the mean of the time playing video games is between 15.4 and 17.8 hours.

d. Which is larger? Explain why.

The margin of error increases as the confidence level increases, due to the value of z, which means that the 99% confidence interval is larger.

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3 years ago

1.5 x 0.41Help with work​

1.5 x 0.41Help with work