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Pepsi [2]
3 years ago
14

The diameter of a circle is 15 ft. Find its circumference in terms of \piπ.

Mathematics
1 answer:
Paladinen [302]3 years ago
7 0
C= 2pi
15= diameter. Radius= 15/2. R= 7.5
C= 2 times pi times 7.2
C=15 pi
C= 47.1
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Since the triangle is a right angle

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A=39 degrees

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Find a polynomial of degree 3 with real coefficients and zeros of -3,-1, and 4, for which f(-2)=-24
Zanzabum

We want to find a polynomial

<em>f(x)</em> = <em>a</em> <em>x</em>³ + <em>b</em> <em>x</em>² + <em>c</em> <em>x</em> + <em>d</em>

such that the roots of <em>f</em> are <em>x</em> = -3, <em>x</em> = -1, and <em>x</em> = 4, and <em>f(x)</em> takes on a value of -24 when <em>x</em> = -2.

The factor theorem for polynomials tells us that we can factorize <em>f(x)</em> as

<em>a</em> <em>x</em>³ + <em>b</em> <em>x</em>² + <em>c</em> <em>x</em> + <em>d</em> = <em>a</em> (<em>x</em> + 3) (<em>x</em> + 1) (<em>x</em> - 4)

Expand the right side:

(<em>x</em> + 3) (<em>x</em> + 1) (<em>x</em> - 4) = <em>x</em>³ - 13<em>x</em> - 12

So we have

<em>a</em> <em>x</em>³ + <em>b</em> <em>x</em>² + <em>c</em> <em>x</em> + <em>d</em> = <em>a x</em>³ - 13<em>a</em> <em>x</em> - 12<em>a</em>

<em />

In order for both sides to be equal, the coefficients of both polynomials on terms of the same degree must be equal. This means

<em>a</em> = <em>a</em> (of course)

<em>b</em> = 0 (there is no <em>x</em>² term on the right)

<em>c</em> = -13<em>a</em>

<em>d</em> = -12<em>a</em>

<em />

We also have that <em>f</em> (-2) = -24, which means

<em>f</em> (-2) = <em>a</em> (-2 + 3) (-2 + 1) (-2 - 4)

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which in turn tells us that <em>c</em> = 52 and <em>d</em> = 48.

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3 years ago
Which of the following triangles are right triangles? select all apply
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Answer:

The following Triangles are Right Triangles:

1.  Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.

2. Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.

3. Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.

Step-by-step explanation:

For a Triangle to be a Right Triangle it must Satisfy Pythagoras theorem.

i.e.

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

For Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.

AC² = 365² = 133225

AB² + BC² = 76² + 357² = 1333225

∴  AC² = AB² + BC²

Hence Δ ABC a Right Triangle.

For Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.

MT² = 845² = 71405

MI² + IT² = 123² + 836² = 714025

∴ MT² = MI² + IT²

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ML² = 101² = 10201

ME² + EL² = 20² + 99² = 10201

∴ ML² = ME² + EL²

Hence Δ MEL a Right Triangle.

7 0
3 years ago
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