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GrogVix [38]
3 years ago
14

Whats 753×5648÷-4519

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
8 0

Answer:

It equals -941.12.... There is a thing caled a calculator you can use for that ;D

Step-by-step explanation:


yawa3891 [41]3 years ago
8 0
The answer is 941.125028
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Answer nine and eleven and how
hammer [34]
Q = 3.
y = 48/4 = 12.
6 0
3 years ago
What number is between 1/6 and 1/4?
stepladder [879]

Answer:

5/24

Step-by-step explanation:

First, we want to get a common denominator, so we multiply them together.

The 2 new fractions are. . .

4/24 (1/6) and 6/24 (1/4)

Now, if you are looking for the number between 4/24 and 6/24, the answer is 5/24.

5 0
2 years ago
Nine tiles are numbered $\color[rgb]{0.35,0.35,0.35}1, 2, 3, \ldots, 9$. Each of three players randomly selects and keeps three
Eduardwww [97]

The probability that all three players obtain an odd sum is 3/14.

<h3>What is probability?</h3>

The probability is the ratio of possible distributions to the total distributions.

I.e.,

Probability = (possible distributions)/(total distributions)

<h3>Calculation:</h3>

Given that,

There are nine tiles - 1, 2, 3,...9, respectively.

A player must have an odd number of odd tiles to get an odd sum. That means he can either have three odd tiles, or two even tiles and an odd tile.

In the given nine tiles the number of odd tiles = 5 and the number of even tiles = 4.

The only possibility is that one player gets 3 odd tiles and the other two players get 2 even tiles and 1 odd tile.

So,

One player can be selected in ^3C_1  ways.

The 3 odd tiles out of 5 can be selected in ^5C_3 ways.

The remaining 2 odd tiles can be selected and distributed in ^2C_1 ways.

The remaining 4 even tiles can be equally distributed in \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !} ways.

So, the possible distributions = ^3C_1 × ^5C_3 × ^2C_1 × \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !}

⇒ 3 × 10 × 2 × 6 = 360

To find the total distributions,

The first player needs 3 tiles from the 9 tiles in ^9C3=84 ways

The second player needs 3 tiles from the remaining 6 tiles in ^6C_3=20 ways

The third player takes the remaining tiles in 1 way.

So, the total distributions = 84 × 20 × 1 = 1680

Therefore, the required probability = (possible distributions)/(total distributions)

⇒ Probability = 360/1680 = 3/14.

So, the required probability for the three players to obtain an odd sum is 3/14.

Learn more about the probability of distributions here:

brainly.com/question/2500166

#SPJ4

3 0
1 year ago
If 8y-8=24, find the value of 2y
algol [13]
8 is the answer
for 2y
6 0
3 years ago
Read 2 more answers
Given m
Lilit [14]

Answer:

x = 41°, y = 139°

Step-by-step explanation:

The given parameters are;

Line <em>m</em> is parallel to line <em>n</em> and lines <em>m</em> and <em>n</em> have a common transversal

The corresponding angles formed by the common transversal to the two parallel lines are 41° on line <em>m</em> and <em>x°</em> on line <em>n</em>

Therefore, x° = 41° by corresponding angles formed between on two parallel lines by a common transversal are equal

x° and y° are linear pair angles and they are, supplementary

∴ x° + y° = 180°

∴ x° + y° = 41° + y° = 180°

y° = 180° - 41° = 139°

y° = 139°.

3 0
3 years ago
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