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photoshop1234 [79]
3 years ago
9

A thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 30° F. Af

ter one-half minute the thermometer reads 60° F. What is the reading of the thermometer at t = 1 min? (Round your answer to two decimal places.)

Mathematics
1 answer:
Slav-nsk [51]3 years ago
5 0

Answer: The reading of the thermometer at t = 1 min is 52.50 °F

Step-by-step explanation: Please see the attachments below

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8 0
3 years ago
Which are partial products for 68 × 43?
blagie [28]

Partial products are the products obtained during the intermediate stages in order to complete a multiplication process.

Consider 68 \times 43, we have to determine the partial products in this.

Now, 68 \times 43

Expanding this, we get

(60+8) \times (40+3)

= (60\times 40) +(60 \times 3) + (8 \times 40) + (8 \times 3)

= 2400 + 180 + 320 + 24

= 2924

Hence, 8 \times 40=320 and 8 \times 3 = 24 are the required partial products in the product of 68 and 43.

So, Option 3 and 4 are the correct answers.

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3 years ago
What is 2x-4+3x+2=48
vivado [14]
96. percent ur welcome kid
4 0
3 years ago
Read 2 more answers
1. For what value(s) of x is the equation below true?<br> 3x over 5=2x over 3
loris [4]

Answer:

0

Step-by-step explanation:

\frac{3x}{5} =\frac{2x}{3}

Cross multiple:

9x=10x

Move them to one side

0=1x

Divide

0=x

8 0
3 years ago
Read 2 more answers
The CEO of a large electric utility claims that more than 75 percent of his customers are very satisfied with the service they r
vichka [17]

Answer:

z=\frac{0.77-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}=0.462  

Now we can find the p value using the alternative hypothesis with this probability:

p_v =P(z>0.462)=0.322  

Since the p value is large enough, we have evidence to conclude that the true proportion for this case is NOT significanctly higher than 0.75 since we FAIL to reject the null hypothesis at any significance level lower than 30%

Step-by-step explanation:

Information provided

n=100 represent the random sample selected

\hat p=0.77 estimated proportion of students that are satisfied

is the value that we want to test

z would represent the statistic

p_v represent the p value

System of hypothesis

We want to verify if more than 75 percent of his customers are very satisfied with the service they receive, then the system of hypothesis is.:  

Null hypothesis:p\leq 0.75  

Alternative hypothesis:p > 0.75  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.77-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}=0.462  

Now we can find the p value using the alternative hypothesis with this probability:

p_v =P(z>0.462)=0.322  

Since the p value is large enough we have evidence to conclude that the true proportion for this case is NOT significanctly higher than 0.75 since we FAIL to reject the null hypothesis at any significance level lower than 30%

4 0
3 years ago
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