Answer:
Find a polynomial function whose graph passes through (6,13), (9,-11), (0,5)
1 Answers
Assuming a quadratic, we have that
y = ax^2 + bx + c
Since (0,5) is on the graph, c =5
And we have the remaining system
a(9)^2 + b(9) + 5 = -11
a(6)^2 + b(6) + 5 = 13 simplify
81a + 9b = -16 multiply through by 6 ⇒ 486a + 54b = - 96 (1)
36a + 6b = 8 multiply through by -9 ⇒ -324a -54b = -72 (2)
Add (1) and (2)
162a = -168
a = -28/27
To find b we have
36 (-28/27) + 6b = 8
-112/3 + 6b = 8
⇒ b = 68/9
The function is
y = - (28/27)x^2 + (68/9)x + 5
Answer:
Value of n is 52
Step-by-step explanation:
So you have equation: 6.2n – 3.7n = 85 + 45
First, you need to collect the like terms and add the numbers on the other side: 2.5n=130
Now, you need to divide both sides of equation by 2.5. And you will get the answer. n=52
If there’s a missing side you subtract the two know angles from 180*. Plug the two angles into the formula a+b+c=180*. i hope this helps :)
1) Mean Absolute Deviation = 1.75
2) Mean = 244
Answer:
IQR: 20
Range: 52
Step-by-step explanation:
IQR = 88 - 68 = 20
Range = 100 - 48 = 52
