The subtracton property of equality allows you to subtract the same amount from both sides of an equation without changing the truth of the equation.
A) Your primary concerns are the points B and E, so y> .5x+4 and y>or= x-4B) choose one or both points, and enter them into the equations. If the statements are true, then the equations work
for problem C So, any point in the shaded area, but not on the line, are valid points for Natalie's school
<u>Answer: </u>
Simplified form of given expression (2x – 9 )( x + 6 ) is 
<u> Solution:
</u>
We need to simplify following expression.
(2x – 9) ( x + 6)
For sake of simplicity lets first assume 2x – 9 = A
So expression becomes A(x+6)
= Ax + A6
Now replace A by 2x – 9
= (2x – 9 ) x + (2x – 9 ) 6
On simplification, we get
Hence simplified form of given expression (2x – 9 )( x + 6 ) is 
SA=4pir²
given SA=12.56
12.56=4pir²
divide both sides by 4
3.14=pir²
3.14=3.14r²
divide both sides by 3.14
1=r²
sqrt both sides
1=r
the radius is 1 in
Answer:
x=8
Step-by-step explanation:
set both equations equal to each other
x^2-3x-10=-2x=2
combine like terms
x^2=1x+8
x+8
Hope this helps!
