3. 3 cm 11 am 6 cm 4.3 cm 8 cm

Alex has a block of wood that is in the shape of a prism with the dimensions shown. He cuts a 10-cm square hole through the cent

eimsori [14]

Answer:

Step-by-step explanation:

I think your question is missing key information and the one below is similar to yours. Hope it will find you well:

"Alex has a block of wood that is in the shape of a rectangular prism dimensions 70 cm by 50 cm by 30 cm. He cuts a 10-cm square hole through the center of the prism. What is the volume of the remaining solid?

Here is my answer:

The volume of the rectangular prism: 70∗50∗30=105000 $cm^{3}$

The volume in the center (intersection of “square holes”): 10∗10∗10=1000 $cm^{3}$

=> the volume of the remaining solid = The volume of the rectangular prism - The volume in the center = 105000 - 1000 = 104000 $cm^{3}$

8 0

3 years ago

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A circle has a radius of 9 inches. The Radius is multiplied by 2/3 to form a second circle. How is the ratio of the areas relate

liraira [26]

Answer:

$\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{r_{1} }{r_{2}}) ^{2}$

The above expression shows that ratios of the areas of the circles are equal to the square of the ratio of their radii.

Step-by-step explanation:

Radius of first circle $(r_{1})$ = 9 inches

Area of first circle = $\pi r_{1} ^{2}$

Area of first circle = 9 × 9 × π = 81 π

Now, since the radius is multiplied by 2/3 for from a new circle.

∴ Radius of the second circle = $9 \times \frac{2}{3} = 6\ inches$

Area of second circle = $\pi r_{2} ^{2}$

Area of second circle = 6 × 6 × π = 36 π

Now,

$\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81\pi }{36\pi }$

$\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{9}{6}) ^{2} = (\frac{r_{1} }{r_{2}}) ^{2}$

∵ $(r_{1})$ = 9 inches and $(r_{2})$ = 6 inches

The above expression shows that ratios of the areas of the circles are equal to the square of the ratio of their radii. i.e., $\frac {radius\ of\ first\ circle)^{2} }{(radius\ of\ second\ circle)^{2} } = \frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)}$

8 0

3 years ago

For I= -1 what is the sum (7+3i) (-8+9)?

amm1812

$(7+3(-1))(-8+9)\\(7-3)(1)\\4$

4

5 0

3 years ago

What is the solution to the system of linear equations?

Ede4ka [16]

I'm pretty sure x = 6 and y = 10

4 * 6 + 3 * 10 = 54
24 + 30 = 54

3 * 6 + 9 * 10 = 108
18 + 90 = 108

I hope this helps. If it does, please mark it as Brainliest

5 0

3 years ago

One-half (1/2) hour equals______________.

Furkat [3]

Answer:

B) 2 one-quarter (1/4) hours

Step-by-step explanation:

1/2 hour = 30 minutes

A) 3/4 = 45 minutes

B) 2/4 = 30 minutes

C) 4/4 = 60 minutes

D) 5/4 = 75 minutes

5 0

3 years ago

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