Answer:
13.19m
Step-by-step explanation:
Divide the total height by the number of step leading
24/91=0.2637 m/step
step 2
Multiply 0.2637 m/step by 50 step
0.2637(50) = 13.19m
Hope this helps!!! :)
Answer:
m∠EGF = 65° and m∠CGF = 115°
Step-by-step explanation:
Given;
∠EFG = 50°
EF = FG
Solution,
In ΔEFG m∠EFG = 50° and EF = FG.
Since triangle is an isosceles triangle hence their base angles are always equal.
∴
Let the measure of ∠EGF be x.
∴ 
Now by angle Sum property which states "The sum of all the angles of a triangle is 180°."
m∠EFG + m∠FEG + ∠EGF = 180
Hence
m∠EGF = 65°
Also 'The sum of angles that are formed on a straight line is equal to 180°."
m∠EGF + m∠CGF = 180°
65° + m∠CGF = 180°
m∠CGF = 180° - 65° = 115°
Hence m∠EGF = 65° m∠CGF = 115°
Answer:
The equation that represents the circle is 
+ 
= 13
Step-by-step explanation:
Given the center of circle (14,9) passes through point (16,12)
We know that the equation of circle is
+ 
= 
where (x,y) is any point on the circle, (h,k) is center of the circle and r is radius of circle.
From given data (x,y) is (16,12) and (h,k) is (14,9). Substituting these values in equation of circle, we get
+ 
=
= 
+ 
= 13
Substituting the values of (h,K) and as (14,9) and 13 respectively in equation of circle, we get
+ = 13
Hence the equation that represents the circle is + = 13
Answer:
There is no picture or graph to go with the question so I am afraid I will not be able to give you a specific answer.
To find out if a point (x, y) is on the graph of a line, we plug in the values into that equation and see if we get a true statement, such as 10 = 10. If we get something different, like 6 = 4, we know that the point is not on the line because it does not satisfy the equation. Plug in (-301, 601) into the equation of the line to see whether that point lies on it or not.
Step-by-step explanation:
Suppose the equation of the straight line that passes through E and F is this:
y = 7x + 2
We are to figure out whether or not the point (1, 10) lies on that line. In order to do this we would plug in (1, 10) into the equation, with 1 being x and 10 being y.
10 = 7(1) + 2 = 7 + 2 = 9
10 = 9 is a false statement. Therefore, the point (1, 10) does NOT lie on the line y = 7x + 2.
If you were to provide an image or graph that shows the equation of line AB then perhaps I would be able to answer your question with a specific answer.
