All categories

3 years ago

Solve for B solve for B A=B+C A=B-C

Mathematics

2 answers:

Mashcka [7]3 years ago

7 0

Your answer would be cba hope this helps

Brums [2.3K]3 years ago

4 0

Answer:

A+B-C=CBA

Step-by-step explanation:

A. x = -2 B. x = 21 C. x = 14 D. x = -14

You might be interested in

6-13x=24-10(2x+8)+62+7x

konstantin123 [22]

Its an Identity, all real numbers are the answer.

4 0

4 years ago

4. An automobile dealership received 11 cars that needed to be detailed. If the

vova2212 [387]

Answer:

11 cars =21/2 hours

Convert 21/2 hours to minutes

60minutes =1hour

2.5 hours =150mins

11cars=150 mins

1 car =1/11×150mins=

150/11=13 7/11mins

7/11to seconds =60 seconds =1minutes

7/11×60secs =38secs

Answer =1car =13mins 38 secs

Step-by-step explanation:

8 0

3 years ago

Subtract 4x +5 from 2x-3

Gnom [1K]

Answer:

-2x-8

Step-by-step explanation:

2x-3 - (4x+5)

Distribute the minus sign

2x-3 -4x-5

Combine like terms

2x-4x-3-5

-2x-8

3 0

3 years ago

Read 2 more answers

Factor the polynomial<br> 16z2 + 25

den301095 [7]

16z^2 + 25

This polynomial is already in lowest terms.

Answer: Cannot be factored.

This happens with certain polynomials.

3 0

3 years ago

Read 2 more answers

Can anyone help me solve a trigonomic identity problem and also help me how to do it step by step?

dusya [7]

$\bf cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\qquad csc(\theta)=\cfrac{1}{sin(\theta)}
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\\\\
-------------------------------\\\\$

$\bf \cfrac{cos(\theta )cot(\theta )}{1-sin(\theta )}-1=csc(\theta )\\\\
-------------------------------\\\\
\cfrac{cos(\theta )\cdot \frac{cos(\theta )}{sin(\theta )}}{1-sin(\theta )}-1\implies \cfrac{\frac{cos^2(\theta )}{sin(\theta )}}{\frac{1-sin(\theta )}{1}}-1\implies 
\cfrac{cos^2(\theta )}{sin(\theta )}\cdot \cfrac{1}{1-sin(\theta )}-1
\\\\\\
\cfrac{cos^2(\theta )}{sin(\theta )[1-sin(\theta )]}-1\implies 
\cfrac{cos^2(\theta )-1[sin(\theta )[1-sin(\theta )]]}{sin(\theta )[1-sin(\theta )]}$

$\bf \cfrac{cos^2(\theta )-1[sin(\theta )-sin^2(\theta )]}{sin(\theta )[1-sin(\theta )]}\implies \cfrac{cos^2(\theta )-sin(\theta )+sin^2(\theta )}{sin(\theta )[1-sin(\theta )]}
\\\\\\
\cfrac{cos^2(\theta )+sin^2(\theta )-sin(\theta )}{sin(\theta )[1-sin(\theta )]}\implies \cfrac{\underline{1-sin(\theta )}}{sin(\theta )\underline{[1-sin(\theta )]}}
\\\\\\
\cfrac{1}{sin(\theta )}\implies csc(\theta )$

7 0

3 years ago