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ch4aika [34]
3 years ago
5

I don't understand this I've done this equation and formula "variable" times but I don't seem to get this one. the formula is y

- y1 = m (x - x1). The first coordinates are (5,1) but I don't know what M = ?
Mathematics
1 answer:
ladessa [460]3 years ago
5 0

Answer:

m = 1  

Step-by-step explanation:

they want an equation that is parallel to the given line and its slope is 1

so  y = x - 4

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Plaese ghelp 5 star thanks
Lena [83]
42x + 4 = 130

42x = 130-4

42x = 126

x = 3
3 0
3 years ago
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Which of the following points lies on the graph of the function y= 2.3*?
Rainbow [258]

If the equation is y = 2\cdot 3^x  (2 times 3^x)

Then the answer is d. (0,2)

This is because plugging x = 0 leads to y = 2 as shown below

y = 2\cdot 3^x\\\\y = 2\cdot 3^0\\\\y = 2\cdot 1\\\\y = 2

3 0
3 years ago
What is the distance between (7, 1), (12, -7)?
OLEGan [10]

Answer:

\sqrt{89}

Step-by-step explanation:

\sqrt{ {(7 - 12)}^{2} +  {(1 - ( - 7))}^{2}  }

\sqrt{ {( - 5)}^{2}  +  {8}^{2} }

\sqrt{25 + 64}

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8 0
2 years ago
Can Someone please answer and explain. It's just one problem and there a picture. Thank you
Mice21 [21]
Vertices (3,0),(-3,0) co-vertices (0,-5),(0,5)

transverse axis (line passing vertices) is on(or parallel to) x-axis then formula is
(x-h)^2/a^2 - (y-k)^2/b^2 = 1
..notice.. x^2 is on positive / y^2 is on negative

center (h,k) is midway between vertices = (0,0)
we have h = k = 0 and now formula is
x^2/a^2 - y^2/b^2 = 1

a is the distance from a vertex to center = 3
b is the distance from a co-vertex to center = 5

the formula is
x^2/3^2 - y^2/5^2 = 1 ... answer is the 1st
6 0
3 years ago
I can’t figure this out. Help!
77julia77 [94]

Answer:

Your answer should be x = \frac{48}{7}.

Hope this helps.

3 0
1 year ago
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