Answer:
c, e, f, and i
Step-by-step explanation:
a. is bounded above at y = 1 and below at y = 0
b. is unbounded both above and below
c. is bounded below at y = 0 and unbounded above
d. is unbounded both above and below
e. is bounded below at y = 0 and unbounded above
f. is bounded below at y = 0 and unbounded above
g. is bounded below at y = 0 and bounded above at y = 1
h. is unbounded both above and below
i. is bounded below at y = 0 and unbounded above
j. is unbounded both above and below
Answer:
B
Step-by-step explanation:
The differences in the terms of f(x) are + 3, + 5, + 7
Since the differences are not constant the relationship is not linear
Note the differences in the differences are + 2, + 2,
The second differences are constant indicating a quadratic relationship
Note the relationship between x and f(x)
x = 1 → 1² = 1 ← require to add 5, that is 1 + 5 = 6 ← value of f(x)
x = 2 → 2² = 4 ← require to add 5, that is 4 + 5 = 9 ← value of f(x)
x = 3 → 3² = 9 ← require to add 5, that is 9 + 5 = 14 ← value of f(x)
x = 4 → 4² = 16 ← require to add 5, that is 16 + 5 = 21 ← value of f(x)
Thus f(x) = x² + 5 → B
Answer:
5
Step-by-step explanation:
6a = (a*-3) + 45
then:
6a = -3a + 45
6a + 3a = 45
9a = 45
a = 45/9
a = 5
Check:
6*5 = (5*-3) + 45
30 = -15 + 45
The answer would be a total of 9 blue stripes.
