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Ne4ueva [31]
4 years ago
6

How to solve this question? please help me

Mathematics
1 answer:
Ber [7]4 years ago
4 0

Use the Pythagorean theorem a^2 + b^2 = c^2

45^2 + 80^2 = c^2

2025 + 6400 = c^2

c^2 = 8425

c = √8425

c = 91.787

Rounded to the nearest foot = 92 feet

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7 0
3 years ago
How do you do this? conculsion statements.
-Dominant- [34]
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The conclusion should be letter B, if Karl runs 1mi, then he runs 5280 ft. In fact, that option is the only one in which you combine the information you have to get a conclusion.
5 0
3 years ago
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I'm very confused on how to even figure out the question and what I'm supposed to do
Tasya [4]

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To solve a system of linear equations graphically we graph both equations in the same coordinate system. The solution to the system will be in the point where the two lines intersect. The two lines intersect in (-3, -4) which is the solution to this system of equations. I hope this helped!

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3 years ago
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rodikova [14]
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7 0
3 years ago
Does the given equation of line form parallel lines or not
malfutka [58]

k:y=m_1x+b_1;\ l:y=m_2x+b_2\\\\k\ \perp\ l\iff m_1\cdot m_2=-1\\\\k\ ||\ l\iff m_1=m_2

k:x+4y=10\ \ \ |-x\\\\4y=-x+10\ \ \ \ |:4\\\\y=-\dfrac{1}{4}x+\dfrac{10}{4}\to m_1=-\dfrac{1}{4}\\\\l:3x-2y=5\ \ \ \ |-3x\\\\-2y=-3x+5\ \ \ \ |:(-2)\\\\y=\dfrac{3}{2}x-\dfrac{5}{2}\to m_2=\dfrac{3}{2}

m_1\neq m_2\to\text{ no parallel}\\\\m_1\cdot m_2=-\dfrac{1}{4}\cdot\dfrac{3}{2}\neq-1\to\text{ no perpendicular}

Answer: NOT PARALLEL

5 0
4 years ago
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