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VMariaS [17]
3 years ago
10

BHJGHJWvhjwvhjdvgjdvgwv

Mathematics
1 answer:
sveta [45]3 years ago
3 0

Answer:

................Uhm not a question.....................................................o/o

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Hey guys I need help with this question
Finger [1]

Answer:

7 1/2 x - 3/4 y

Step-by-step explanation:

8 0
3 years ago
A survey conducted by the Consumer Reports National Research Center reported, among other things, that women spend an average of
Nookie1986 [14]

Answer:

(a) The probability that a randomly selected woman shop exactly two hours online is 0.217.

(b) The probability that a randomly selected woman shop 4 or more hours online is 0.0338.

(c) The probability that a randomly selected woman shop less than 5 hours online is 0.9922.

Step-by-step explanation:

Let <em>X</em> = time spent per week shopping online.

It is provided that the random variable <em>X</em> follows a Poisson distribution.

The probability function of a Poisson distribution is:

P (X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0,1,2,...

The average time spent per week shopping online is, <em>λ </em>= 1.2.

(a)

Compute the probability that a randomly selected woman shop exactly two hours online over a one-week period as follows:

P (X=2)=\frac{e^{1.2}(1.2)^{2}}{2!} =0.21686\approx0.217

Thus, the probability that a randomly selected woman shop exactly two hours online is 0.217.

(b)

Compute the probability that a randomly selected woman shop 4 or more hours online over a one-week period as follows:

P (X ≥ 4) = 1 - P (X < 4)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

              =1-\frac{e^{1.2}(1.2)^{0}}{0!}-\frac{e^{1.2}(1.2)^{1}}{1!}-\frac{e^{1.2}(1.2)^{2}}{2!}-\frac{e^{1.2}(1.2)^{2}}{3!}\\=1-0.3012-0.3614-0.2169-0.0867\\=0.0338

Thus, the probability that a randomly selected woman shop 4 or more hours online is 0.0338.

(c)

Compute the probability that a randomly selected woman shop less than 5 hours online over a one-week period as follows:

P (X < 5) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

              =\frac{e^{1.2}(1.2)^{0}}{0!}+\frac{e^{1.2}(1.2)^{1}}{1!}+\frac{e^{1.2}(1.2)^{2}}{2!}+\frac{e^{1.2}(1.2)^{3}}{3!}+\frac{e^{1.2}(1.2)^{4}}{4!}\\=0.3012+0.3614+0.2169+0.0867+0.0260\\=0.9922

Thus, the probability that a randomly selected woman shop less than 5 hours online is 0.9922.

8 0
4 years ago
Kayla knows that 1/16
Anastasy [175]

Answer:

The quotient is 0. 0625  and the empty boxes in remainder are 4 and 8 respectively

Step-by-step explanation:

Given: \frac{1}{16} or 1 divided by 16

Step 1: dividend is 1 and divisor 16 it is not divisible by 16  so the Quotient is 0 remainder is 1 .

Step 2: taking the decimal point above now dividend is 10 and divisor is 16 so it is again not divisible by 16 so the  quotient is 0.0 and remainder is 10 now bringing next 0 in remainder so the dividend becomes 100.

Step 3: now dividend is 100 and divisor is 16 which is divisible by 16 by 6 times which is 96 so the Quotient becomes 0.06 and remainder becomes 4 now bringing next 0 in remainder so the dividend becomes 40.

Step 4: now dividend is 40 and divisor is 16 which is divisible by 16 by 2 times which is 32 so the Quotient becomes 0.062 and remainder becomes 8 now bringing next 0 in remainder so the dividend becomes 80.

Step 5: now dividend is 80 and divisor is 16 which is divisible by 16 by 5 times which is 80 so the Quotient becomes 0.0625 and remainder becomes 0

5 0
3 years ago
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:( :( :( :( im sad im just sad like really really sad
tiny-mole [99]

Answer:

I hope you feel better

Step-by-step explanation: don’t be sad

3 0
3 years ago
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A 40 ft power boat is on sale by owner. How long is the boat to the nearest yard?
andriy [413]
<span>3 feet make 1 yard.
40 feet make 13 and 1/3 yards
So that is 13 yards to nearest </span>
8 0
3 years ago
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