Answer:
t = -1.862, df = 399, p > 0.05
Step-by-step explanation:
The null hypothesis is the statement which is test for its validity. The decision to accept or reject the null hypothesis is based on the test statistics value. In the given question the null hypothesis is H0 = 34. There is one sample t-test for the testing of null hypothesis. The null hypothesis will be same for each type of one sample t-test. The null hypothesis assumes that the difference between the true mean and comparison value is zero.
Answer:
15 nickels and 13 dimes
Step-by-step explanation:
5n + 10d = 205 cents
n + d = 28
n = 28-d
5(28-d) +10d = 205
140 -5d + 10d = 205
5d = 65
d = 13
n = 28-d = 28-13 = 15
5n = 5(15) = 75
10d = 10(13) = 130
75+130=205
The correct answer is B, hope this helps
Answer with explanation:
The confidence interval for population mean is given by :-
, where n= Sample size
= Sample mean
= Standard deviation
z* = Critical z-value.
Let be the average age at first marriage of women.
As per given ,we have
n= 5,534 ,
Sample standard deviation : s= 4.7
Since n is extremely very large so we assume that this scenario follows a normal distribution , and thus we can use z-test .
So ,
Critical value of 95% confidence level : z=1.96
Put all values in formula , we get
Hence , our 95% confidence interval =(23.38, 23.62)
Interpretation : The National Survey of Family Growth can be 95% sure that the true population mean age at first marriage of women lies in (23.38, 23.62) .