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2 years ago

Name the equation for any horizontal line of your choosing

Mathematics

1 answer:

noname [10]2 years ago

3 0

Answer:

Horizontal lines have a slope of 0. Thus, in the slope-intercept equation y = mx + b, m = 0. The equation becomes y = b, where b is the y-coordinate of the y-intercept.

Step-by-step explanation:

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I need help with this math problem.

statuscvo [17]

Answer:

Step-by-step explanation:

Intial fee is x. Number of stops is y. You can set up these equations.

x+4y=8
x+8y=14
x+12y=20

You can subtract one from the other:

x+8y=14

- x+4y=8

–––––––

4y=6

We now know that 4y=6. The first equation had 4y, so we can put 6 instead of 4y.

x+6=8
Subract 6, x=2

8 0

3 years ago

REALLY NEED HELP IM STUCK. I PUT A PICTURE

azamat

Just look at the x and y variables and their exponents and roots. Ignore the rest.

Start with x.
On the left side you have cubic root of x^c.
On the right side you have x^2.

$\sqrt[3]{x^c} = x^2$

$(x^c)^{\frac{1}{3}} = x^2$

$\dfrac{c}{3} = 2$

$c = 6$

Now look at y on both sides and the roots and exponents of y.

$\sqrt[3]{y^5} = y\sqrt[3]{y^d}$

$(y^5)^{\frac{1}{3}} = y^1 \times y^{\frac{d}{3}}$

$y^{\frac{5}{3}} = y^{1 + \frac{d}{3}}$

$y^{\frac{5}{3}} = y^{\frac{3}{3} + \frac{d}{3}}$

$y^{\frac{5}{3}} = y^{\frac{d + 3}{3}}$

$\dfrac{d + 3}{3} = \dfrac{5}{3}$

$d + 3 = 5$

$d = 2$

Answer: Choice C. c = 6; d = 2

5 0

3 years ago

Z Points

vazorg [7]

Answer:

The equation of the line (-1/2, 3) and (0, 0) is y = -6x

Solution:

Given, two points are ( $\frac{-1}{2}$ , 3) and (0, 0)

We have to find the line equation that passes through the given two points.

Now, we know that, line equation that passes through $\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)$ is given by:

$y-y_{1}=\left(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\right)\left(x-x_{1}\right)$

Here in our problem, $x_{1}=0, y_{1}=0, x_{2}= \frac{-1}{2} \text { and } y_{2}=3$

Substitute these values in above formula.

$y-0=\left(\frac{3-0}{\frac{-1}{2}-0}\right)(x-0) \rightarrow y=\frac{3}{\frac{-1}{2}} \times x \\\\\rightarrow y=3 \times\left(\frac{-2}{1}\right) \times x \rightarrow y=-6 x$

Hence the equation of the line (-1/2, 3) and (0, 0) is y = -6x

6 0

3 years ago

Re-write the quadratic function below in Standard Form 2 y = -(x – 4)2 + 8

svetlana [45]

Answer:

y=-x+8

Step-by-step explanation:

First distribute the negative

2y=(-x+4)2+8

then you would multiply the (-x+4) by the two

2y=-2x+8+8

then you would combined like terms

2y=-2x+16

then you would divide both sides by 2

y=-x+8

8 0

3 years ago

The sum of two numbers is 19. Their difference is 65. What are the numbers?

Ludmilka [50]

X = 42 and y = - 23 are the two numbers

3 0

3 years ago