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2 years ago

(a) It takes 40 pounds of seed to completely plant a 6-acre field. How many pounds of seed are needed per acre? poundsperacre

Mathematics

1 answer:

lakkis [162]2 years ago

6 0

Answer: 6 2/3 or 6.67 pounds per acre (depending on how you write it)

Step-by-step explanation:

40 pounds/ 6 acres

= 6 2/3 or 6.67 pounds per acre

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1) Find the general solution to the following differential equation x^3•y’- y = 0

maxonik [38]

Answer:

y(x) = c_1 e^(-1/(2 x^2))

Step-by-step explanation:

Solve the separable equation x^3 (dy(x))/(dx) - y(x) = 0:

Solve for (dy(x))/(dx):

(dy(x))/(dx) = y(x)/x^3

Divide both sides by y(x):

((dy(x))/(dx))/y(x) = 1/x^3

Integrate both sides with respect to x:

integral((dy(x))/(dx))/y(x) dx = integral1/x^3 dx

Evaluate the integrals:

log(y(x)) = -1/(2 x^2) + c_1, where c_1 is an arbitrary constant.

Solve for y(x):

y(x) = e^(-1/(2 x^2) + c_1)

Simplify the arbitrary constants:

Answer: y(x) = c_1 e^(-1/(2 x^2))

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2 years ago

a moving company charges $250 to rent a truck and $0.40 for each mile driven. Mr. Lee paid a total of $314. Which equation can b

Llana [10]

The equation would be
314 = 0.4(x) + 250
Would you like me to explain?

3 0

3 years ago

Find the value of r ,so that the line passing through the points 6,2 and 10,r given and has a slope of 2

bonufazy [111]

Answer:

Step-by-step explanation:

Slope (m) of two points is expressed as :

m = (y2 - y1) / (x2 - x1)

Given m = 2

the equation becomes;

2 = (r - 2) / (10 - 6)

2 = (r - 2) / 4

cross multiplying becomes ;

2 * 4 = r - 2

8 = r - 2

r = 10

7 0

2 years ago

Abdul can type 23 words per minute.

Phantasy [73]

Answer:

1. 1035 words

2. 21.74 min

Step-by-step explanation:

1. 23 words per min × 45min = 1035 words

2. 500 words/ 23 words per min= 21.74 min

8 0

2 years ago

Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case

olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = Dave will show up.

<em>M</em> = Mike will show up.

Given:

$P(D^{c})=0.55\\P(M^{c})=0.45$

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

$P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25$

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

$=1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75$

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

$P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25$

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0

3 years ago

Read 2 more answers