Answer:
Q10. 21 doses; Q 11. 21 doses; Q12. 42 bottles
Step-by-step explanation:
Question 10
(a) Calculate the total ounces
![\text{Total ounces} = \text{7 da} \times \dfrac{\text{3 times}}{\text{1 da}} = \dfrac{\frac{1}{2}\text{ oz}}{\text{1 time}}= \text{10.5 oz}](https://tex.z-dn.net/?f=%5Ctext%7BTotal%20ounces%7D%20%3D%20%5Ctext%7B7%20da%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B3%20times%7D%7D%7B%5Ctext%7B1%20da%7D%7D%20%20%3D%20%5Cdfrac%7B%5Cfrac%7B1%7D%7B2%7D%5Ctext%7B%20oz%7D%7D%7B%5Ctext%7B1%20time%7D%7D%3D%20%5Ctext%7B10.5%20oz%7D)
(b) Calculate the number of doses
![\text{Number of doses} = \text{10.5 oz } \times \dfrac{\text{1 dose}}{\frac{1}{2}\text{ oz}} = \textbf{21 doses}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20doses%7D%20%3D%20%5Ctext%7B10.5%20oz%20%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20dose%7D%7D%7B%5Cfrac%7B1%7D%7B2%7D%5Ctext%7B%20oz%7D%7D%20%3D%20%5Ctextbf%7B21%20doses%7D)
Question 11
![\text{Number of doses} = \text{7 da} \times \dfrac{\text{3 doses}}{\text{1 da}} = \textbf{21 doses}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20doses%7D%20%3D%20%5Ctext%7B7%20da%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B3%20doses%7D%7D%7B%5Ctext%7B1%20da%7D%7D%20%3D%20%5Ctextbf%7B21%20doses%7D)
Question 12
(a) Convert ounces to litres
![\text{Volume} = \text{2 oz} \times \dfrac{\text{29.57 mL}}{\text{1 oz}} \times \dfrac{\text{1 L}}{\text{1000 mL}} = \text{0.05914 L}](https://tex.z-dn.net/?f=%5Ctext%7BVolume%7D%20%3D%20%5Ctext%7B2%20oz%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B29.57%20mL%7D%7D%7B%5Ctext%7B1%20oz%7D%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20L%7D%7D%7B%5Ctext%7B1000%20mL%7D%7D%20%3D%20%5Ctext%7B0.05914%20L%7D)
(b) Calculate the number of bottles
![\text{No of bottles} = \text{2.5 L} \times \dfrac{\text{1 bottle}}{\text{0.059 14 L}} = \textbf{42 bottles}](https://tex.z-dn.net/?f=%5Ctext%7BNo%20of%20bottles%7D%20%3D%20%5Ctext%7B2.5%20L%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20bottle%7D%7D%7B%5Ctext%7B0.059%2014%20L%7D%7D%20%3D%20%5Ctextbf%7B42%20bottles%7D)
The domain and the range of a function are the set of input and output values, the function can take.
- <em>The domain and the range of </em>
<em> is </em>
<em>.</em> - <em>The parent function </em>
<em> is vertically compressed by 9, then shifted down by 5 units to get </em>
<em />
<em />
Given
![g(x) = 9x^2 - 2](https://tex.z-dn.net/?f=g%28x%29%20%3D%209x%5E2%20-%202)
<u>Domain and range</u>
There is no restriction as to the input and the output of function g(x).
This means that the domain and the range are
is in interval notation
The corresponding set notation is: ![- \infty < x < \infty](https://tex.z-dn.net/?f=-%20%5Cinfty%20%3C%20x%20%3C%20%5Cinfty)
<u />
<u>The parent function</u>
We have:
![f(x) = x^2](https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%5E2)
First, the parent function is vertically compressed by a factor of 9.
The rule of this transformation is:
![(x,y) \to (x,9y)](https://tex.z-dn.net/?f=%28x%2Cy%29%20%5Cto%20%28x%2C9y%29)
So, we have:
![f'(x) = 9x^2](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%209x%5E2)
Next, the function is shifted down by 5 units.
So, we have:
![g(x) = f'(x) - 5](https://tex.z-dn.net/?f=g%28x%29%20%3D%20f%27%28x%29%20-%205)
![g(x) = 9x^2 - 5](https://tex.z-dn.net/?f=g%28x%29%20%3D%209x%5E2%20-%205)
Read more about functions at:
brainly.com/question/21027387
506 x - 92 y + 90 = 498 - 4 x + 6 y
Geometric figure:
line
y = (255 x)/49 - 204/49
510 x - 98 y - 408 = 0
506 x - 92 y + 90 = 6 (y + 83) - 4 x
Real solution:
y = (255 x)/49 - 204/49
Solution:
y = (255 x)/49 - 204/49
Integer solution:
x = 49 n + 40, y = 255 n + 204, n element Z
Solution for the variable y:
y = 51/49 (5 x - 4)
Let's solve for d.
fd=(7)(1.06)d
Step 1: Add -7.42d to both sides.
df+−7.42d=7.42d+−7.42d
df−7.42d=0
Step 2: Factor out variable d.
d(f−7.42)=0
Step 3: Divide both sides by f-7.42.
d(f−7.42)f−7.42=0f−7.42
d=0f−7.42
Answer:
d=0f−7.42
PLEASE MARK ME AS BRAINLIEST
Answer:
12
Step-by-step explanation:
Waterfalls to Canoes = 6 units
Canoes to Fishing Area = 6 units
Total = 6+6 = 12